awk command and variable assignment

Question

I have a MyFile.xml whose contents are as below

<root>
    <Main>
            <someothertag>..</someothertag>
        <Amt Ccy="EUR">13</Amt>
    </Main>
                .
                .
                .
                some other tags
    <Main>
          <someothertag>..</someothertag>
             <Amt Ccy="SGD">10</Amt>
    </Main>
    <another>
      <Amt Ccy="EUR">10</Amt>
     </another>
</root>

I have script file whose contents are as below

result = `awk '/<Main>/ { f=1 } f && /Amt/ { split($0,a,/[<>]/); s+=a[3] } /<\/Main>/ { f=0 } END {print  s }' MyFile.xml`
echo "The result is " $result

But i am getting output as

result: 0653-690 Cannot open =.
result: 0653-690 Cannot open 23.
The result is

My Expected output is

The result is 23

http://stackoverflow.com/questions/2268104/basic-bash-script-variable-declaration-command-not-found/2268117#2268117 — William Pursell, Dec 27 '12 at 14:21

score 0 · Accepted Answer · answered Dec 27 '12 at 11:15

0

When assigning variables there should be no spaces on either side of the =.

Change to:

result=`awk '/<Main>/ { f=1 } f && /Amt/ { split($0,a,/[<>]/); s+=a[3] } /<\/Main>/ { f=0 } END {print  s }' MyFile.xml`

answered Dec 27 '12 at 11:15

dogbane

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awk command and variable assignment

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