Sort array by two values

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Simple function to sort an array of objects

While writing the script, there was a problem with sorting an array. I have an array of objects:

[{gold: false, range: 1601}, {gold: true, range: 13}, {gold: false, range: 375}, {gold: true, range: 601}

But it should look like this:

[{gold: true, range: 13}, {gold: true, range: 601}, {gold:false, range: 375}, {gold: false, range: 1601}]

I want to get an array in which the keys are sorted by increasing range. But if there gold key value is true, then they are the first.

explain your problem in details – Manish Nagar Dec 29 '12 at 12:27 — Manish Nagar, Dec 29 '12 at 12:27

SergeyS · Accepted Answer · 2012-12-29T12:50:44.223

Use something like this:

yourArray.sort(function(a, b){
    return a["gold"] == b["gold"] ? a["range"] - b["range"] : a["gold"] ? -1 : 1;
});

Or even this:

yourArray.sort(function(a, b){
    return  b["gold"] - a["gold"] || a["range"] - b["range"];
});

The second approach is really cool actually)) You can just use this pattern for any number of fields in your object, just order them by their importance. If some field should be sorted as ascending - than a["..."] - b["...], if as descending - than b["..."] - a["..."]

score 3 · Answer 2 · answered Dec 29 '12 at 12:28

Try

var arr = [{gold: false, range: 1601}, {gold: true, range: 13}, {gold: false, range: 375}, {gold: true, range: 601}], 
    sorter = function(a, b) {
      if(a.gold && !b.gold) {return -1;}
      if(!a.gold && b.gold) {return 1;}
      return a.range - b.range;
    };

arr.sort(sorter);

Sort array by two values

2 Answers2