How can I rethrow Exception?

Question

Possible Duplicate:
Is there a way to throw an exception without adding the throws declaration?

I wonder if there is a way to encapsulate Exception and rethrow it in another Exception when method is already defined and don't have throws clause.

An example (with JMS onMessage method) :

 public void onMessage(Message message) {

    if(message instanceof ObjectMessage){

        ObjectMessage objectMessage = (ObjectMessage)message;

        try {
            Object object = objectMessage.getObject();
        } catch (JMSException e) {
            throw new CustomException("blah blah", e); // ERROR HERE : Unhandled exception type CustomException
        }

     }

 }

So, how can I encapsulate and dispatch CustomException in my code please ? Is there a way ? Thanks

score 4 · Answer 1 · answered Dec 29 '12 at 14:43

4

You need to use a subclass of RuntimeException.

answered Dec 29 '12 at 14:43

bmargulies

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score 3 · Answer 2 · answered Dec 29 '12 at 14:47

3

If a method does not declare any exceptions, the only way is to throw an exception which subclasses of RuntimeException.

In your case CustomException should extend RuntimeException.

A bit of theory from Oracle on Exceptions.

answered Dec 29 '12 at 14:47

Tom

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score 1 · Answer 3 · edited May 23 '17 at 12:18

1

This would have worked if CustomException was an unchecked exception (run time exception). You can read about checked vs unchecked exceptions here - Java: checked vs unchecked exception explanation

edited May 23 '17 at 12:18

Community

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answered Dec 29 '12 at 14:49

Manish Mulani

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How can I rethrow Exception?

3 Answers3