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I have two instances of IEnumerable<T> (with the same T). I want a new instance of IEnumerable<T> which is the concatenation of both.

Is there a built-in method in .NET to do that or do I have to write it myself?

Pang
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Samuel Rossille
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    You might want to bookmark http://code.msdn.microsoft.com/101-LINQ-Samples-3fb9811b. – C-Pound Guru Jan 04 '13 at 21:21
  • related, if it helps: [Elegant way to combine multiple collections of elements?](http://stackoverflow.com/questions/4493858/elegant-way-to-combine-multiple-collections-of-elements) – nawfal May 31 '15 at 10:16

6 Answers6

450

Yes, LINQ to Objects supports this with Enumerable.Concat:

var together = first.Concat(second);

NB: Should first or second be null you would receive a ArgumentNullException. To avoid this & treat nulls as you would an empty set, use the null coalescing operator like so:

var together = (first ?? Enumerable.Empty<string>()).Concat(second ?? Enumerable.Empty<string>()); //amending `<string>` to the appropriate type
JohnLBevan
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Jon Skeet
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26

The Concat method will return an object which implements IEnumerable<T> by returning an object (call it Cat) whose enumerator will attempt to use the two passed-in enumerable items (call them A and B) in sequence. If the passed-in enumerables represent sequences which will not change during the lifetime of Cat, and which can be read from without side-effects, then Cat may be used directly. Otherwise, it may be a good idea to call ToList() on Cat and use the resulting List<T> (which will represent a snapshot of the contents of A and B).

Some enumerables take a snapshot when enumeration begins, and will return data from that snapshot if the collection is modified during enumeration. If B is such an enumerable, then any change to B which occurs before Cat has reached the end of A will show up in Cat's enumeration, but changes which occur after that will not. Such semantics may likely be confusing; taking a snapshot of Cat can avoid such issues.

supercat
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10

You can use below code for your solution:-

public void Linq94() 
{ 
    int[] numbersA = { 0, 2, 4, 5, 6, 8, 9 }; 
    int[] numbersB = { 1, 3, 5, 7, 8 }; 

    var allNumbers = numbersA.Concat(numbersB); 

    Console.WriteLine("All numbers from both arrays:"); 
    foreach (var n in allNumbers) 
    { 
        Console.WriteLine(n); 
    } 
}
Jay Shukla
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10

I know this is a relatively old post, but if you wanted to concatenate multiple IEnumerable's, I use the following

var joinedSel = new[] { first, second, third }.Where(x => x != null).SelectMany(x => x);

This eliminates any null IEnumerable's and allows for multiple concatenations.

craig1231
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1

Based off of craig1231's answer, I've created some extension methods...

    public static IEnumerable<T> JoinLists<T>(this IEnumerable<T> list1, IEnumerable<T> list2)
    {
        var joined = new[] { list1, list2 }.Where(x => x != null).SelectMany(x => x);
        return joined ?? Enumerable.Empty<T>();
    }
    public static IEnumerable<T> JoinLists<T>(this IEnumerable<T> list1, IEnumerable<T> list2, IEnumerable<T> list3)
    {
        var joined = new[] { list1, list2, list3 }.Where(x => x != null).SelectMany(x => x);
        return joined ?? Enumerable.Empty<T>();
    }
    public static IEnumerable<T> JoinMany<T>(params IEnumerable<T>[] array)
    {
        var final = array.Where(x => x != null).SelectMany(x => x);
        return final ?? Enumerable.Empty<T>();
    }
-3
// The answer that I was looking for when searching
public void Answer()
{
    IEnumerable<YourClass> first = this.GetFirstIEnumerableList();
    // Assign to empty list so we can use later
    IEnumerable<YourClass> second = new List<YourClass>();

    if (IwantToUseSecondList)
    {
        second = this.GetSecondIEnumerableList();  
    }
    IEnumerable<SchemapassgruppData> concatedList = first.Concat(second);
}
aloisdg
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Hasse
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