Is it possible to time out python 3 input? I managed to do what I want in Java, but how can you do it in python? Can you use jython and manage to compile it so that it doesn't need a jython installation to run (I only have python available on the target computer)?
import java.io.IOException;
public class TimedRead {
public static String timedRead(int timeout) {
long startTime = System.currentTimeMillis();
long endTime = 0;
char last = '0';
String data = "";
while(last != '\n' && (endTime = System.currentTimeMillis()) - startTime < timeout) {
try {
if(System.in.available() > 0) {
last = (char) System.in.read();
data += last;
}
} catch (IOException e) {
e.printStackTrace();
return "IO ERROR";
}
}
if(endTime - startTime >= timeout) {
return null;
} else {
return data;
}
}
public static void main(String[] args) {
String data = timedRead(3000);
System.out.println(data);
}
}
Thanks.
EDIT:
I was able to throw an error to cause the thread to halt.
import signal
#This is an "Error" thrown when it times out
class Timeout(IOError):
pass
def readLine(timeout):
def handler(signum, frame):
#Cause an error
raise Timeout()
try:
#Set the alarm
signal.signal(signal.SIGALRM, handler)
signal.alarm(timeout)
#Wait for input
line = input()
#If typed before timed out, disable alarm
signal.alarm(0)
except Timeout:
line = None
return line
#Use readLine like you would input, but make sure to include one parameter - the time to wait in seconds.
print(readLine(3))