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How can I escape the forward slashes in the regex when using the matches constraint? This is what I tried:

constraints {
    url (
        matches: "^http://www.google.com/$"
    )
}

Error: solution: either escape a literal dollar sign "\$5" or bracket the value expression "${5}"

constraints {
    url (
        matches: "^http:\/\/www.google.com\/$"
    )
}

Error: unexpected char: '\'

zoran119
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1 Answers1

10

In strings defined with double quotes ("..") groovy replaces variables with $.

def var = "world"
def str = "hello $var" // "hello world"

In your validation regex this is causing an error. You want to use the $ for a regular expression and not for variable replacement. To avoid variable replacement you can define strings in single quotes ('..')

def str = 'hello $var' // "hello $var"

You don't need to escape / when defining the regular expression inside a string but you you should escape .. In a regular expression . matches any character. So the regular expression ^http://www.google.com/$ matches http://wwwAgoogleB.com/.

To escape a character inside a string you have to use \\ (the first \ is for escaping the second \). So the following expression should work:

static constraints = {
    name (
        matches: '^http://www\\.google\\.com/$'
    )
}

Normally you could also use the groovy regular expression syntax (/../). It this case the regular expression would look like this

~/^http:\/\/www\.google\.com\/$/

You don't need double backslashes for escaping but therefore you have to escape slashes (because they are used for terminating the regular expression). But as far as I know this syntax does not work with the matches constraint from grails.

micha
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    +1. "slashy-string" syntax does work but you don't need the leading `~`. In groovy `/foo/` is just an alternative syntax for string literals. The `~` operator can go in front of any string (single quoted, double quoted or slashy) as a shorthand for `Pattern.compile` to turn the string into a `Pattern`. – Ian Roberts Jan 05 '13 at 11:06