<?php
$str = "02";
$int = 1;
$result = $str-$int;
echo $result // 1
?>
But I need result = 01
Don't tell me "0".$str-$int;
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4 Answers
5
<?php
$str = "02";
$int = 1;
printf('%02d', $str-$int);
or
<?php
$str = "02";
$int = 1;
$result = sprintf('%02d', $str-$int);
// do something with $result here
VolkerK
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If I want to make variable ? – l2aelba Jan 08 '13 at 13:37
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1@l2aelba you would use `sprintf()` instead. +1 this is a better solution. – kittycat Jan 08 '13 at 13:39
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l2aelba: then you'd use sprintf as shown at http://stackoverflow.com/a/14216162/4833 – VolkerK Jan 08 '13 at 13:39
4
try
printf("%02d",$str-$int);
The explanation of the numerous formatting possibilities of printf are explained in the sprintf docs
fvu
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3
<?
$str = "02";
$int = 1;
echo sprintf("%02d", (int)$str - $int);
?>
skurton
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`echo sprintf()` is an "antipattern". There is absolutely no reason that anyone should ever write `echo sprintf()` in any code for any reason -- it should be `printf()` without `echo` every time. – mickmackusa Apr 09 '22 at 02:44
1
Use str_pad() where you set it to pad the left with 0's until the length of string is 2 chars.
echo str_pad($str - $int, 2, '0', STR_PAD_LEFT);
kittycat
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2@l2aelba, I would use VolkerK's answer as it is a better approach to do it. – kittycat Jan 08 '13 at 13:42