Makefile how to specify program arguments

Question

I have written a small c program and created a Makefile to compile and execute it. Basically, I do the following:

$ make
$ make run

But, my executable requires some arguments, so I would like to specify them this way:

$ make run arg1 arg2

Is it possible to achieve that?

Have a look here if it helps you http://stackoverflow.com/questions/2214575/passing-arguments-to-make-run — Arpit, Jan 10 '13 at 19:03
Does the executable need these arguments to compile? Or just to execute? I usually use Make to compile, then ./executable arg1 arg2. — PinkElephantsOnParade, Jan 10 '13 at 19:05
One more http://stackoverflow.com/questions/2826029/passing-additional-variables-from-command-line-to-make — Satish, Jan 10 '13 at 19:06
No, I just want to use make run arg1 instead of ./executable arg1 — kaspersky, Jan 10 '13 at 19:07
@Satish, it is a trivial Makefile. Just all target, with gcc x.c -o x and run target with ./x. — kaspersky, Jan 10 '13 at 19:19
Is there a reason that `make run` is easier than `./myProg`? — altendky, Jan 10 '13 at 23:03

Satish · Accepted Answer · 2013-01-10T20:59:08.327

2

How about this?

Makefile

 demo: demo1.c
            cc -o demo1 demo1.c
 run:
            ./demo1 $A $B

Passing argument as a variable A and B

[spatel@mg0008 tmp]$ make run A=2 B=3
./demo1 2 3
2 + 3 = 5

edited Jan 10 '13 at 20:59

answered Jan 10 '13 at 19:49

Satish

1 Answers1