regular expression ~ extract string

Question

I need to extract using Regular Expression from following string

console.log("This can be anything except double quote"),

followed by comma and any other string

and the extraction output is

console.log("This can be anything except double quote"),

Note that the sample string shall not be read literally (e.g. can be anything means a random string or symbol

~!@#$%^&*)

Any idea, what is the right regular expression for above case?

score 0 · Answer 1 · answered Jan 12 '13 at 04:58

0

There are many solutions to this. The simplest I could think of: (console.log[^,]+)

PS: This removes the comma at the end of the console statement. You can manually add that.

answered Jan 12 '13 at 04:58

Srinivas

sorry, i dont understand the logic, are you assuming that inside double quote there is no comma? – iwan Jan 12 '13 at 06:06

score 0 · Accepted Answer · edited May 23 '17 at 12:24

0

(console\.log\("(?:[^"\\]|\\.)*"\),)

edited May 23 '17 at 12:24

Community

answered Jan 12 '13 at 05:02

nneonneo

sample = 'console.log("Test regex =>"), abcdef'; sample.match('console\.log\("(?:[^"\\]|\\.)*"\),') – iwan Jan 12 '13 at 06:04
thank nneonneo, i tested in ruby with above 2 lines code , it gave me error "premature end of char-class: /console\.log\("(?:[^"\]|\.)*"\),/ (RegexpError)" – iwan Jan 12 '13 at 06:05
You're right nneonneo, i should have changed single quote to slash in Ruby. THANKS A LOT. – iwan Jan 12 '13 at 06:43

2 Answers2