MVVM Light and one instance of an application

Question

I am developing a WPF application using MVVM Light.

I would like to know how to check and prevent the user from running more than one instance of the application?

Thank you for your help.

Romain

score 2 · Answer 1 · answered Jan 18 '13 at 10:17

2

Arik Poznanski write an article about this subject on his blog.

Here is the link to the first article

And here is the link to the update

answered Jan 18 '13 at 10:17

Romain

121
2

score 1 · Answer 2 · answered Jan 13 '13 at 08:07

You can check running processes on application startup and exit if copy is already present:

var appProcessName = Process.GetCurrentProcess().ProcessName;
var matchingProcesses = Process.GetProcessesByName(appProcessName);
if (matchingProcesses.Any())
{
    // Exit
}

score 0 · Answer 3 · edited May 23 '17 at 11:45

0

I think what you are looking for is called a single instance mutex. Google has many results, but I used one recently from this thread for a Windows Forms app.

https://stackoverflow.com/a/7810107/1718702

edited May 23 '17 at 11:45

Community

1
1

answered Jan 13 '13 at 08:21

HodlDwon

1,131
1
13
30

Yes, I have looked for it on Google before but I did not find any results pertaining to MVVM light. Actually I want to know where to put the code to check for the instance. In App.xaml.cs? In MainViewModel.cs? – Romain Jan 13 '13 at 09:29
Ah, I don't have any experience with mvvm. Sorry :( – HodlDwon Jan 13 '13 at 09:35
Did you find out how to do it? The App StartUp event which is the right place to put a mutex for a single instance application on a common WPF scenario is not working. – Pantelis Dec 06 '13 at 08:11

MVVM Light and one instance of an application

3 Answers3