I'm having trouble adding the value of type="button"
form elements to a mySql database, and I'm wondering if I'm missing something.
Edit - It doesn't look like the information for that element is being passed from the html to the php because it's not echoing a value. My only problem is with this one element and the rest of the form is being submitted properly.
I'm using this for an online quiz which builds a user profile based upon images they've selected, and am setting the images as background images for the button elements, and I'm trying to do this in straight html (as opposed to using javascript together with radio buttons or check boxes).
<input type="button" name="quiz_start" value="jeans" style="background: url(files/start1.jpg) no-repeat; width:54px;height:140px; cursor:pointer; border:none; color: transparent; font-size : 0">
I've simplified the php code for purposes of asking the question (including specifying the user id and limiting it to only one field). I've also included the full code below.
<?php
//Start session & connect to database
$user_id = 3;
$qry = "INSERT INTO style(user_id, quiz_start) VALUES('$user_id','$_POST[quiz_start]')";
$result = @mysql_query($qry);
header("location: page2.html");
exit();
?>
The full query is:
$fieldlist=$vallist='';
foreach ($_POST as $key => $value) {
$fieldlist.=$key.',';
$vallist.='\''.($value).'\',';
}
$fieldlist=substr($fieldlist, 0, -1);
$vallist=substr($vallist, 0, -1);
$fieldlist.=', user_id';
$vallist.=','.$user_id;
$setlist='';
foreach ($_POST as $key=>$value){
$setlist.=$key .'=\''.$value.'\',';
}
$setlist=substr($setlist, 0, -1);
$result = mysql_query('UPDATE style SET '.$setlist.' WHERE user_id='.$user_id);
if (mysql_affected_rows()==0) {
$result = mysql_query('INSERT INTO style ('.$fieldlist.') VALUES ('.$vallist.')');
}
header("location: page2.html");
exit();
?>