$raw_results=mysql_query("SELECT resort_name FROM resorts WHERE resort_id=(SELECT resort_id FROM resort_place WHERE place_id=(SELECT place_id FROM place WHERE place='$query')) ") or die(mysql_error());
$check_num_rows=mysql_num_rows($raw_results);
$solutions = array();
while($row = mysql_fetch_assoc($raw_results)) {
$solutions[] = $row['solution'];
}
This is my code and it returns an error message like
Warning: mysql_query() [function.mysql-query]: Unable to save result set in C:\xampp\htdocs\search\news.php on line 131 Subquery returns more than 1 row
can any one help me to retrieve the values from the data base...