19

On Windows I can call:

_time32(__time32_t); // to get 32-bit time_t
_time64(__time64_t); // to get 64-bit time_t

(both in 32 and 64-bit programs)

Is there any way do this in Linux (compiling with GCC)?

phuclv
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chiyer
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  • @Benoit That question is not a duplicate, it's completely different. – interjay Jan 16 '13 at 15:40
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    Not really...on 32-bit Linux, `time_t` is a traditional 32-bit signed quantity, with only 25 years of useful life left in it. On 64-bit Unix systems, it is already a 64-bit quantity. If you want a portable type, you'll have to define your own that maps appropriately, or just use `time_t` carefully. The other question referenced has relevant information (but I agree it is not a duplicate). – Jonathan Leffler Jan 16 '13 at 15:56
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    see also **[64-bit UNIX Timestamp Conversion](http://stackoverflow.com/questions/7914368/64-bit-unix-timestamp-conversion)** – Janus Troelsen Mar 13 '14 at 19:46

5 Answers5

16

Many answers above said that this is impossible, but that's entirely incorrect. It was not possible at that time yet people had been talking about fixing it for years. Finally 64-bit time support on 32-bit platforms was introduced to the Linux 5.1 kernel with the addition of the new *time64 syscalls. Look at this table you can see that those syscalls are only available on 32-bit platforms. Now if you're writing code for 32-bit systems you can call clock_gettime64 directly (from inline assembly or C with syscall()) to get the current time

However after that you're completely on your own. If you want full userspace support you must be on Linux 5.6 or higher along with musl 1.2+ or glibc 2.32+. Just rebuild your code and your time_t will become 64-bit long

  • All user space must be compiled with a 64-bit time_t, which will be supported in the coming musl-1.2 and glibc-2.32 releases, along with installed kernel headers from linux-5.6 or higher.

  • Applications that use the system call interfaces directly need to be ported to use the time64 syscalls added in linux-5.1 in place of the existing system calls. This impacts most users of futex() and seccomp() as well as programming languages that have their own runtime environment not based on libc.

https://lkml.org/lkml/2020/1/29/355?anz=web

For more information

phuclv
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  • On my 32 bit Linux 5.4 i can't call `clock_gettime64` etc. It tells me undefined reference. What do I need to include/define/install in order for it to work? – arminb Apr 13 '21 at 09:02
  • @arminb how do you call it? It's a system call, not a C function. In C you'll need to use `syscall()` as I mentioned above, but you need to know how to put the syscall number and how to put all the register values – phuclv Apr 13 '21 at 10:17
  • Yes, I know, I call it like this: `syscall(SYS_clock_gettime64, ...);`. It says "error: 'SYS_clock_gettime64' undeclared ... did you mean 'SYS_clock_gettime" – arminb Apr 13 '21 at 10:24
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    @arminb you can see how it's called in [musl](https://git.musl-libc.org/cgit/musl/tree/src/time/clock_gettime.c#n75). See also [this](https://github.com/richfelker/musl-cross-make/issues/96). If that doesn't help then please ask that in another question – phuclv Apr 13 '21 at 10:43
  • @phuclv is it possible to compile a 32 bit ARM architecture with 64 bit `time_t`? – D. Smith Jun 08 '21 at 12:40
  • @D.Smith yes, of course. If you have the appropriate versions of kernel and libc then just compile the code and `time_t` will automatically be 64-bit as I said. If you have the correct kernel but not libc then do the syscall manually: `syscall(403, CLOCK_REALTIME, custom_timespec_struct);` with 403 being the [syscall number for clock_gettime64](https://marcin.juszkiewicz.com.pl/download/tables/syscalls.html) in ARM – phuclv Jun 08 '21 at 12:46
  • @phuclv I have compiled a custom Linux 5.10 with custom gcc toolchain using glibc 2.32 and `sizeof(time_t)` still returns 4, `__TIMESIZE` is still set to 32. I'm not sure how to achieve 64 bit `time_t`. – D. Smith Jun 08 '21 at 13:27
  • @D.Smith I think there are some issues with your custom gcc. Please ask a separate question on that – phuclv Jun 08 '21 at 13:29
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    @phuclv I have: https://stackoverflow.com/questions/67884032/glibc-set-timesize – D. Smith Jun 08 '21 at 13:53
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    Just popped in to add: on musl, and I believe in glibc, it's not necessary to have a kernel with time64 support in order to use 64-bit time_t. On an older kernel, you'll be limited not to set the current time or file timestamps past Y2038, but you can still use the new ABI for applications and they'll be all ready to go when you move to a newer kernel. – R.. GitHub STOP HELPING ICE Dec 08 '21 at 21:22
  • Apparently you actually need glibc 2.34+ (not 2.32+). Also, you *must* enable LFS (large file support) or the compilation will fail. This is annoying because you can't just force _TIME_BITS=64 regardless of architecture, you need to actually detect you're on 32-bits and THEN force-enable _TIME_BITS=64, and the LFS defines, otherwise you get compilation errors... – anonymous Mar 03 '23 at 17:00
15

Apparently, no it's not possible. For starters, there is only one time() function in Linux, no time32() or time64().

After searching for a while, I can see that it's not libc's fault, but the culprit is actually the kernel.

In order for libc to fetch the current time, it need to execute a system call for it: (Source)

time_t time (t) time_t *t;
{
    // ...
    INTERNAL_SYSCALL_DECL (err);
    time_t res = INTERNAL_SYSCALL (time, err, 1, NULL);
    // ...
    return res;
}

The system call is defined as: (Source)

SYSCALL_DEFINE1(time, time_t __user *, tloc)
{
    time_t i = get_seconds();
    // ...
    return i;
}

The function get_seconds() returns an unsigned long, like so: (Source)

unsigned long get_seconds(void)
{
    struct timekeeper *tk = &timekeeper;

    return tk->xtime_sec;
}

And timekeeper.xtime_sec is actually 64-bit: (Source)

struct timekeeper {
    // ...
    /* Current CLOCK_REALTIME time in seconds */
    u64                     xtime_sec;
    // ...
}

Now, if you know your C, you know that the size of unsigned long is actually implementation-dependant. On my 64-bit machine here, it's 64-bit; but on my 32-bit machine here, it's 32-bit. It possibly could be 64-bit on some 32-bit implementation, but there's no guarantee.

On the other hand, u64 is always 64-bit, so at the very base, the kernel keeps track of the time in a 64-bit type. Why it then proceeds to return this as an unsigned long, which is not guaranteed to be 64-bit long, is beyond me.

In the end, even if libc's would force time_t to hold a 64-bit value, it wouldn't change a thing.

You could tie your application deeply into the kernel, but I don't think it's even worth it.

netcoder
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    So, write a patch and post it. Both for libc (typedef long long int time_t) and the kernel long long int get_seconds(void) – user877329 May 12 '14 at 09:57
  • @user877329 changing the type of existing functions breaks many things, so new syscalls had to be introduced for 64-bit time instead. See below – phuclv Nov 04 '20 at 09:54
7

No time64()/time32() function are included into standard libraries.

No time32_t/time64_t defines are contemplated in standard headers.

time_t is defined into time.h as typedef __time_t time_t;

Following a long chain of redefines, you'll discover that __time_t is defined as 32 bit on 32 bit machines and 64bit on 64 bit machines.

Davide Berra
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1

Use this library: https://github.com/evalEmpire/y2038

The goal of this project is to provide a drop-in replacement for POSIX time.h which will work on machines which have a 32-bit time_t, yet not suffer from the 2038 bug. This will allow C programmers to be 2038-safe without having to rewrite their software to a new interface. It does this while still using the system time zone database.

amadvance
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-4

If you really need this, why not roll your own?

typedef int32_t my_time32;
typedef int64_t my_time64;


my_time32 get_mytime32() {
    if (sizeof(time_t) == sizeof(my_time32))
        return time(NULL);
    else {
        /* Check for overflow etc. here... */
        return (my_time32)(time(NULL));
    }
}

And similarly for get_mytime64().

If you do not care about overflow, a simple return time(NULL); would work for both functions thanks to C's implicit numeric conversions.

Nemo
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    I don't think a simple return time(NULL); would work for get_mytime64() on 32-bit platforms - it would just truncate. – rsaxvc Jul 12 '16 at 12:03
  • @rsaxvc Yes hence the "check for overflow etc here" comment. In general you have a problem dealing with 32-bit times – Nemo Jul 12 '16 at 19:53