How print array if he created in function?

Question

Arrays created in function test().

Then I would like print their on page test.php.

My code down:

conf.php

function test(){
$str= array(
        'items' => array(
                0 => array(
                        'title' => 'Title',
                        'category' => 'Category name',
                        ),
                1 => array(
                        'title' => 'Title',
                        'category' => 'Category name',
                        ),
        ),
        'details' => array(
                'firstname' => 'firstname',
                'lastname' => 'lastname',
        ),
        'Id' => $Id,
        'OrderId' => 'fsdfsfdsrew'
);


$json = json_encode($str);
$base64 = base64_encode($json);

$sig = signMessage($base64, $secretPhrase);
}

test.php

require_once("conf.php");

test();
print_r($str);
print_r($json);
print_r($base64);
print_r($sig);

Tell me please why code not worked?

Tell me please why weren't printed $str, $json, $base64, and $sig?

How do it?

Preferably without global parameters.

`return $str;` from your function and call as `$str = test();` — Michael Berkowski, Jan 17 '13 at 15:43
@MichaelBerkowski I would like print all arrays, bot one only — , Jan 17 '13 at 15:44
If you need to return all of those ( just noticed they're all created in the funciton) you need to return them as an array. — Michael Berkowski, Jan 17 '13 at 15:45
`return array('str' =>$str,'json'=>$json','base64'=>$base64,'sig'=>$sig);` — Michael Berkowski, Jan 17 '13 at 15:45
Call the same way as `$ret = test();` and print as `print_r($ret['json']);` etc... — Michael Berkowski, Jan 17 '13 at 15:48

Ray · Accepted Answer · 2013-01-17T15:50:56.040

You can't without returning them as the function return value. In PHP, variables declared in a function (the arrays you're trying to print_r in this case) are only available within the scope of that function unless you declare them global with the global keyword.

Here's the details on variable scope in PHP: http://php.net/manual/en/language.variables.scope.php

You could construct a larger array to contain these arrays and return them from the test() function:

 function test(){
     //function code here....
     ////...

     $results = array('str'=> $str, 
                      'json'=> $json, 
                      'base64'=>$base64, 
                      'sig' => signMessage($base64, $secretPhrase)
                  ) ;

      return $results;
  }

Then call it like this:

  $results = test();
  print_r($results['str']);
  print_r($results['sjson']);
  print_r($results['base64']);
  print_r($results['sig']);

i known this, but i would like know how print their if i created `return array('str' =>$str,'json'=>$json','base64'=>$base64,'sig'=>$sig);` — , Jan 17 '13 at 15:52

Guerra · Answer 2 · 2013-01-17T16:06:16.020

0

Many ways to do that: first, you have to return the value if you want use on other class. on your test you can do:

$something = new Conf();
$someelse = $something->test();
echo $someelse;

edited Jan 17 '13 at 16:06

answered Jan 17 '13 at 15:46

Guerra

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in your Conf.php on the first line make class Conf { methods code } – Guerra Jan 17 '13 at 15:55
@Guerra you call non-static methods of classes with `->` not `.` in PHP. – Ray Jan 17 '13 at 16:00
@Ray you're right, sorry. Java programer thing – Guerra Jan 17 '13 at 16:06

How print array if he created in function?

2 Answers2