PHP ternary operator error

Question

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PHP ternary operator not working as expected

I dont know what is wrong with my code? My PHP Version is 5.4.7.

$b = 'a';
$c = 'd';
echo $b == 'a' ? 2: $c == 'a' ? 1 : 0; 

output 1

right answer should be 2.....

Thank you very much for your advice.

The **language manual** clearly states: [It is recommended that you avoid "stacking" ternary expressions. PHP's behaviour when using more than one ternary operator within a single statement is non-obvious:](http://us.php.net/ternary#example-121). — DCoder, Jan 18 '13 at 13:16

Vlad Preda · Accepted Answer · 2013-01-18T13:21:44.283

8

You need to add some parenthesis.

$b = 'a';
$c = 'd';
echo ($b == 'a') ? 2 : ($c == 'a' ? 1 : 0);

edited Jan 18 '13 at 13:21

answered Jan 18 '13 at 13:15

Vlad Preda

Thank you very much! May I ask why this will not work in php?? – Micah Jan 18 '13 at 13:16
I mean the way I got wrong, it should be right in js – Micah Jan 18 '13 at 13:16
2

The best answer to this was given by @DCoder. I recommend reading his link. – Vlad Preda Jan 18 '13 at 13:20

1 Answers1