In my WPF application I use the Console Window as a debug/message window - I have options setup to show and hide the window as the user desires and all that works great. The only issue is that when the user closes the Console window it exits the entire program. How can I override this so that when the user click on the X it just hides the Console instead of exiting the application?
this is what I have so far:
const int SW_HIDE = 0;
const int SW_SHOW = 5;
public static bool ConsoleVisible { get; private set; }
[DllImport("kernel32.dll")]
static extern IntPtr GetConsoleWindow();
[DllImport("user32.dll")]
static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);
public static void HideConsole()
{
var handle = GetConsoleWindow();
ShowWindow(handle, SW_HIDE);
ConsoleVisible = false;
}
public static void ShowConsole()
{
var handle = GetConsoleWindow();
ShowWindow(handle, SW_SHOW);
ConsoleVisible = true;
}
** For people wanting to utilize this you need: using System.Runtime.InteropServices;
This code was derived from this answer: https://stackoverflow.com/a/3571628/649382
** Edit **
Looking around a bit more it seems like this is not possible. I saw an answer here: https://stackoverflow.com/a/12015131/649382 that talks about removing the exit button which would also be acceptable, except it looks like the code is in C++ and I can't figure out it's C# alternative.
** Edit 2 **
I was able to figure out the conversion to C# and have written it as the answer below.