how to actiavte fancybox after submit button pressed or how to let the user show sign up screen using fancybox after submit

Question

Desired Operation : User will fill out the html form and when press the submit button then I want to validate the user type and if it is guest then it should show a fancybox(popup) screen to sign up for that user because I dont want to save values with guest user. The code I have mentioned in the question is fine but HOW CAN I ACTIVATE THE FANCYBOX SCREEN AFTER VALIDATING THE USER.

I am trying

if($_SESSION['FIRST_NAME']=="Guest")
{
// here I want the code to show the signup.php page
print '<a id="loginframe" href="Signup.php">Sign Up here</a>';
}

How would I activate the fancybox screen coz I dont want to show the link but the activated fancybox firectly with the signup.php iframe. (fancybox is working fine)

You can use `$array[index]` without quotes though I personally would not recommend doing this. — mishmash, Jan 22 '13 at 12:13

score 0 · Accepted Answer · edited May 23 '17 at 10:24

If possible, I suggest that you avoid using iframes in this particular case.

What I would do is use AJAX to submit the form. That way, the page will not be reloaded and you'll have a js callback function where you can trigger Fancybox. (Jquery.ajax, jQuery Form)

Here is how you can programatically trigger Fancybox:

How to programatically trigger fancybox with an inline div?

I hope this helps.

how to actiavte fancybox after submit button pressed or how to let the user show sign up screen using fancybox after submit

1 Answers1