PHP, Get tomorrows date from date

Question

I have a PHP date in the form of 2013-01-22 and I want to get tomorrows date in the same format, so for example 2013-01-23.

How is this possible with PHP?

John Conde · Accepted Answer · 2014-01-07T18:58:29.383

231

Use DateTime

$datetime = new DateTime('tomorrow');
echo $datetime->format('Y-m-d H:i:s');

Or:

$datetime = new DateTime('2013-01-22');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');

Or:

$datetime = new DateTime('2013-01-22');
$datetime->add(new DateInterval("P1D"));
echo $datetime->format('Y-m-d H:i:s');

Or in PHP 5.4+:

echo (new DateTime('2013-01-22'))->add(new DateInterval("P1D"))
                                 ->format('Y-m-d H:i:s');

edited Jan 07 '14 at 18:58

answered Jan 22 '13 at 14:12

John Conde

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1

This uses current, I need to pass in a given date. – Justin Jan 22 '13 at 14:13

score 109 · Answer 2 · edited Dec 29 '21 at 13:38

109

 $tomorrow = date("Y-m-d", strtotime('tomorrow'));

or

  $tomorrow = date("Y-m-d", strtotime("+1 day"));

Help Link: STRTOTIME()

edited Dec 29 '21 at 13:38

entio

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answered Dec 15 '15 at 09:47

Laura Chesches

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I used this one and of all answers is the shortest and simplest version, thanks ! – Bombelman May 06 '20 at 03:23
This is cool and will also give you yesterday: `-1 day` – bwoogie Apr 30 '21 at 21:53

score 17 · Answer 3 · edited May 23 '17 at 12:34

17

Since you tagged this with strtotime, you can use it with the +1 day modifier like so:

$tomorrow_timestamp = strtotime('+1 day', strtotime('2013-01-22'));

That said, it's a much better solution to use DateTime.

edited May 23 '17 at 12:34

Community

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answered Jan 22 '13 at 14:14

Rudi Visser

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score 15 · Answer 4 · edited Dec 17 '13 at 21:42

15

<? php 

//1 Day = 24*60*60 = 86400

echo date("d-m-Y", time()+86400); 

?>

edited Dec 17 '13 at 21:42

richard

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answered Oct 24 '13 at 10:35

andy

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Note that this will fail in edge cases (daylight savings time). – JJJ Jul 06 '14 at 17:01
This answer is wrong. I have a cronjob use this in a loop, and the system got died. – jewelnguyen8 Nov 07 '19 at 08:40

score 8 · Answer 5 · answered Jun 22 '17 at 05:12

8

echo date ('Y-m-d',strtotime('+1 day', strtotime($your_date)));

answered Jun 22 '17 at 05:12

ABDUL JAMAL

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score 5 · Answer 6 · answered Jun 27 '17 at 01:18

Use DateTime:

To get tomorrow from now :

$d = new DateTime('+1day');
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 28/06/2017 08.13.20

To get tomorrow from a date :

$d = new DateTime('2017/06/10 08.16.35 +1day')
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 11/06/2017 08.16.35

Hope it helps!

score 1 · Answer 7 · answered Jun 09 '15 at 16:26

/**
 * get tomorrow's date in the format requested, default to Y-m-d for MySQL (e.g. 2013-01-04)
 *
 * @param string
 *
 * @return string
 */
public static function getTomorrowsDate($format = 'Y-m-d')
{
    $date = new DateTime();
    $date->add(DateInterval::createFromDateString('tomorrow'));

    return $date->format($format);
}

score 1 · Answer 8 · edited Feb 02 '16 at 13:14

1

By strange it can seem it works perfectly fine: date_create( '2016-02-01 + 1 day' );

echo date_create( $your_date . ' + 1 day' )->format( 'Y-m-d' );

Should do it

edited Feb 02 '16 at 13:14

Markus Safar

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answered Feb 02 '16 at 12:51

Diogo Neves - Mangaru

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score -1 · Answer 9 · answered Jan 31 '17 at 08:53

-1

here's working function

function plus_one_day($date){
 $date2 = formatDate4db($date);
 $date1 = str_replace('-', '/', $date2);
 $tomorrow = date('Y-m-d',strtotime($date1 . "+1 days"));
 return $tomorrow; }

answered Jan 31 '17 at 08:53

Muhammad Awais Zulifqar

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what does the formatDate4db function do? Why replace the dashes with slashes in the string? – braindigitalis Aug 12 '19 at 13:33
formatDate4db function pass the date and it make a format like database mysql format , and str_replace function , i have date format 2019/12/10 and replace with - – Muhammad Awais Zulifqar Dec 19 '19 at 14:03

score -4 · Answer 10 · answered Jan 22 '13 at 14:14

-4

$date = '2013-01-22';
$time = strtotime($date) + 86400;
echo date('Y-m-d', $time);

Where 86400 is the # of seconds in a day.

answered Jan 22 '13 at 14:14

Jason

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No, one day doesn't always have 86400 seconds. – nickb Jan 22 '13 at 14:15
I don't get the problem. Please explain @nickb – Aiyion.Prime Dec 05 '15 at 21:35
@Aiyion.Prime days that make the switch to or from daylight saving time do not have 86400 seconds – dumazy Dec 07 '15 at 10:07
I thought of that, DST is initiated at two o'clock and should therefore never result in a different date? – Aiyion.Prime Dec 07 '15 at 18:19
The problem isn't daylight savings. Times in a database really should be stored as UTC which has no daylight saving time. If you're storing your dates in UTC this will work fine but is a bit obtuse. – braindigitalis Dec 31 '19 at 20:12

PHP, Get tomorrows date from date

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