I've seen in http://docs.jboss.org/hibernate/orm/3.3/reference/en/html/objectstate.html
Use the Hibernate Session to make an object persistent
But I don't know if it means literally using Session. Explanation: I get the following error when saving an instance:
org.springframework.dao.InvalidDataAccessApiUsageException: object references an unsaved transient instance - save the transient instance before flushing: xxxxxxx.entities.Sujeto.progTtipoSujeto -> xxxx.entities.TipoSujeto; nested exception is org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: xxxxx.entities.Sujeto.progTtipoSujeto -> xxxxx.entities.TipoSujeto
at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:651)
at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible(HibernateJpaDialect.java:92)
at org.springframework.orm.jpa.JpaTransactionManager.doCommit(JpaTransactionManager.java:460)
I know the reason is that Sujeto.progTtipoSujeto is of type TipoSujeto, and it's just been instantiated before saving the Sujeto instance. Besides, the field progTtipoSujeto is joint to an identifier field:
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "IDN_TIPO_SUJETO", insertable = false, updatable = false)
private TipoSujeto progTtipoSujeto;
@Column(name = "IDN_TIPO_SUJETO")
private Integer idnTipoSujeto;
The solution I've been given (it works) is to fetch it from the database before saving:
parserSujetoToEntity.parserSujetoToEntity(sujetoDTO, sujetoEntity);
TipoSujeto tipoSujetoEntity = (TipoSujeto) this.findByPrimaryKey(TipoSujeto.class, sujetoDTO.getTipo());
sujetoEntity.setProgTtipoSujeto(tipoSujetoEntity);
this.save(sujetoEntity);
Is there a way to do the same using Session?
