Could not create query metamodel on simple JPA repository

Question

I defined the following repository

public interface CityVerboseRepository extends JpaRepository<CityVerbose, Integer>{
    List<CityVerbose> findByStreetStartingWith(String street);      
}

corresponding to the entity

@Entity
public class CityVerbose {
    @Id
    public Integer id;

    public String street;
}

but all I am getting is

could not create query metamodel for method public abstract java.util.List

once I am trying to autowire that repository. All my other repositories work just fine...

Have you tried to rename your interface to `CityVerboseRepositoryCustom`? — flash, Jan 23 '13 at 15:03
but it is not a customer repository, isn't it? The Custom Repository issue, that needs exact naming convention only applies if I am actually implementing the interface, but not if I am just extending it. but sure I try — MatthiasLaug, Jan 23 '13 at 15:05
1.0.1 does not support that in the jpa repo. updated and worked fine :( removed the stacktrace for cleanup — MatthiasLaug, Jan 23 '13 at 15:13
Rename your method to findAllxxx if you want to return a collection for consistency reasons. — Marcel Stör, Jan 23 '13 at 19:37

score 1 · Accepted Answer · answered Jan 23 '13 at 15:13

1

The startingWith syntax is not available in 1.0.3.RELEASE of spring data. Updated to 1.2.0.RELEASE and everything worked fine

answered Jan 23 '13 at 15:13

MatthiasLaug

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Could not create query metamodel on simple JPA repository

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