Regex for extracting 3 digits numbers between brackets

Question

My string is:

Frequency/FA ID VerifiedFA0 FAID5(125)/FA1 FAID7(175)/FA2 FAID1(476)

The regex I'm trying to create should extract these numbers:

125, 175, 476

I did it by looking at this example but there must be a better one.

myString.replaceAll(".+\\(([0-9]+)\\).+\\(([0-9]+)\\).+\\(([0-9]+)\\).*","$1,$2,$3")

What is wrong with the solution you have? What exactly is your question? — Till Helge, Jan 29 '13 at 20:07
Here is a java regex testing site: http://www.cis.upenn.edu/~matuszek/General/RegexTester/regex-tester.html — DwB, Jan 29 '13 at 20:11
@Till Helge Helwig, I'm trying to find better one because i will need it soon for similar tasks. — Ned, Jan 29 '13 at 20:22

Rohit Jain · Answer 1 · 2013-01-29T20:20:19.523

Rather than replacing everything that you don't need, you can use Pattern and Matcher class, to extract what you need.

The regex pattern to extract numbers between brackets would be: -

\(\d+\)

+ quantifier is used to match 1 or more repetition of digits. If you want to match just 3 digits, then you can use {3} quantifier with \d: - \(\d{3}\).

You can apply this regex pattern with Matcher#find() method to get all the numbers from that string. I leave the task of implementation to you.

score 3 · Accepted Answer · answered Jan 29 '13 at 20:30

Check this out:

String s = "Frequency/FA ID VerifiedFA0 FAID5(125)/FA1 FAID7(175)/FA2 FAID1(476)";
Pattern patt = Pattern.compile("\\(\\d+\\)");
Matcher match = patt.matcher(s);
while(match.find()){
    System.out.println(match.group());
}

score 1 · Answer 3 · edited Feb 20 '19 at 19:05

1

Slight change:

This finds exactly 3 digits inside of parentheses: ((\d\d\d))

The actual string value (in java) is: "(\\(\\d\\d\\d\\))"

Test on the Java RegEx Test page

edited Feb 20 '19 at 19:05

isherwood

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answered Jan 29 '13 at 20:17

DwB

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Regex for extracting 3 digits numbers between brackets

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