Problem
What is the fastest method to order a flat unordered set of nodes such that the parent is always listed before it's children. My current solution uses a queue to iterate the tree in a breadth first manner. However I've been wondering if there was a better / more efficient method.
Notes:
- I can't pre compute any values
- Id and ParentId could also be Guids (even if ints I can't guarantee sequential ids)
Linq Pad Code
void Main()
{
var nodes = new Node[] {
new Node { Id = 7, ParentId = 3 },
new Node { Id = 4, ParentId = 2 },
new Node { Id = 1, ParentId = 0 },
new Node { Id = 2, ParentId = 1 },
new Node { Id = 3, ParentId = 1 },
new Node { Id = 5, ParentId = 2 },
new Node { Id = 6, ParentId = 3 },
new Node { Id = 8, ParentId = 0 },
};
SortHierarchy(nodes).Dump();
}
IEnumerable<Node> SortHierarchy(IEnumerable<Node> list)
{
// hashtable lookup that allows us to grab references to the parent containers, based on id
var lookup = new Dictionary<int, List<Node>>();
Queue<Node> nodeSet = new Queue<Node>();
List<Node> children;
foreach (Node item in list) {
if (item.ParentId == 0) { // has no parent
nodeSet.Enqueue(item); // This will add all root nodes in the forest
} else {
if (lookup.TryGetValue(item.ParentId, out children)) {
// add to the parent's child list
children.Add(item);
} else {
// no parent added yet
lookup.Add(item.ParentId, new List<Node> { item });
}
}
}
while (nodeSet.Any()) {
var node = nodeSet.Dequeue();
if (lookup.TryGetValue(node.Id, out children)) {
foreach (var child in children) {
nodeSet.Enqueue(child);
}
}
yield return node;
}
}
private class Node {
public int Id { get; set; }
public int ParentId { get; set; }
public string Name { get; set; }
}
Research
I did find this however it wasn't quite what I was after (also the code doesn't work)