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My app needs to generate a hex string to use as a session ID. Java's SecureRandom doesn't seem to be working ("java/lang/NoClassDefFoundError: java/security/SecureRandom: Cannot create class in system package")

I thought of doing something like this:

byte[]  resBuf = new byte[50];
new Random().nextBytes(resBuf);
String  resStr = new String(Hex.encode(resBuf));

But the method nextBytes(byte[] bytes) isn't available for some strange reason.

Does anyone have a means of generating a random hex number in Java ME/J2ME?

Many thanks.

Edit: The above generator seems to work when using Bouncy Castle lcrypto-j2me-145 (but not lcrypto-j2me-147).

Bataleon
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1 Answers1

58

JavaME is a subset of JavaSE, so many classes and methods in the desktop version are not available.

Looks like you are trying to get a random string of a given length. You can do something like this:

    private String getRandomHexString(int numchars){
        Random r = new Random();
        StringBuffer sb = new StringBuffer();
        while(sb.length() < numchars){
            sb.append(Integer.toHexString(r.nextInt()));
        }

        return sb.toString().substring(0, numchars);
    }
Mister Smith
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    Since `Integer.toHexString` strips leading zeroes, the first character of the hex is never zero, except for the rare case where `Random.nextInt()` returns 0. Instead of `Integer.toHexString`, one can use `String.format("%08x", r.nextInt())`. – laurt Jul 16 '19 at 12:06