105

I am new to asynchronous programming, so after going through some async sample codes, I thought of writing a simple async code

I created a simple Winform application and inside the Form I wrote the following code. But its just not working

private Task<string> methodAsync() {
    Thread.Sleep(10000);
    return "Hello"; //Error: Cannot implicitly convert type 'string' to 'System.Threading.Tasks.Task<string>'
}

private async void button1_Click(object sender, EventArgs e)
{
    string s = await methodAsync();
    MessageBox.Show(s);
}

Could someone please put some light here..

techBeginner
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5 Answers5

162

The listed return type of the method is Task<string>. You're trying to return a string. They are not the same, nor is there an implicit conversion from string to Task<string>, hence the error.

You're likely confusing this with an async method in which the return value is automatically wrapped in a Task by the compiler. Currently that method is not an async method. You almost certainly meant to do this:

private async Task<string> methodAsync() 
{
    await Task.Delay(10000);
    return "Hello";
}

There are two key changes. First, the method is marked as async, which means the return type is wrapped in a Task, making the method compile. Next, we don't want to do a blocking wait. As a general rule, when using the await model always avoid blocking waits when you can. Task.Delay is a task that will be completed after the specified number of milliseconds. By await-ing that task we are effectively performing a non-blocking wait for that time (in actuality the remainder of the method is a continuation of that task).

If you prefer a 4.0 way of doing it, without using await , you can do this:

private Task<string> methodAsync() 
{
    return Task.Delay(10000)
        .ContinueWith(t => "Hello");
}

The first version will compile down to something that is more or less like this, but it will have some extra boilerplate code in their for supporting error handling and other functionality of await we aren't leveraging here.

If your Thread.Sleep(10000) is really meant to just be a placeholder for some long running method, as opposed to just a way of waiting for a while, then you'll need to ensure that the work is done in another thread, instead of the current context. The easiest way of doing that is through Task.Run:

private Task<string> methodAsync() 
{
    return Task.Run(()=>
        {
            SomeLongRunningMethod();
            return "Hello";
        });
}

Or more likely:

private Task<string> methodAsync() 
{
    return Task.Run(()=>
        {
            return SomeLongRunningMethodThatReturnsAString();
        });
}
Servy
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    how can I explicitly wrap `string` in `Task`? OR isn't there any way to return `Task` or `Task` without using `async` and `await` in the method being called(methodAsync in this case)? – techBeginner Feb 02 '13 at 02:39
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    @Aniket No, you're wrong, there are plenty of ways of explicitly wrapping a string in a task. I'll edit a solution in. – Servy Feb 02 '13 at 02:42
  • @Servy: suppose if I am not using the delay and some other code instead, which is causing the same delay in `methodAsync`, how shall I return the result string by wrapping it in Task? – techBeginner Feb 02 '13 at 02:53
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    You can use Task.FromResult to wrap a string in a Task. – Ameen Feb 02 '13 at 02:54
  • @dotNETbeginner If you aren't `await`ing anything, or starting a new task, then you're blocking the current thread (which is the UI thread, given where you've called it) and you need to...not be doing that. See second edit. – Servy Feb 02 '13 at 02:57
  • @Ameen That would be making the method synchronous, not asyncohronous, and would only cause further problems (namely the UI freezing). – Servy Feb 02 '13 at 02:58
  • @Servy: anyway I am `await`-ing in `button1_Click` then, how am I blocking the UI thread by not awaiting in `methodAsync`? – techBeginner Feb 02 '13 at 03:04
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    @dotNETbeginner Well, you can try it for yourself if you don't believe me. `await` means, start that task, once it's started add a continuation to that task and continue on with the method where I left off once the async task finishes. If you just used `Sleep` and then `Task.FromResult` in the async method it would spend the entire 10 seconds just starting the task, never returning back to the caller until it's completed, thus blocking the UI thread the whole time and effectively running the entire thing synchronously. – Servy Feb 02 '13 at 05:08
  • @Servy: its not the question of believing you.. by questioning I am trying to know something from you or trying to understand something which I am not able to or trying to get the questions clarified which are rising in my mind..Please don't misinterpret as I am doubting your answer..for that matter I have already accepted your answer.. – techBeginner Feb 02 '13 at 07:40
  • @Servy ! you really know how to explain something. Great answer. – Jannie Theunissen Jul 26 '13 at 10:30
  • Task.FromResult is what I was looking for, so thanks. – Gordon Tucker Oct 01 '13 at 21:35
  • With the 4.0 way of doing it (without using await) you can pass reference parameters. With `async` you cannot. – GDavoli Feb 19 '22 at 07:52
  • @GDavoli But you can't close over a reference parameter in a lambda, for exactly the same reason you can't use reference parameters in async methods, so it's not actually useful, it's just going to fail at a different place. – Servy Feb 19 '22 at 19:35
76

Use FromResult Method

public async Task<string> GetString()
{
   System.Threading.Thread.Sleep(5000);
   return await Task.FromResult("Hello");
}
Jaswant Agarwal
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    thanks this is exactly what I needed, which none of the other answers provided. – John Henckel Jul 28 '16 at 14:03
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    As far as I can tell this answer is the best way to implement an interface defined with a Task with an implementation that is synchronous – Simon_Weaver Dec 06 '17 at 04:54
  • Isn't it possible to avoid the "async" and "await"? public Task GetString() { System.Threading.Thread.Sleep(5000); return Task.FromResult("Hello"); } – Mahou5 Sep 28 '22 at 14:34
27

Beyond the problematic use of async as pointed out by @Servy, the other issue is that you need to explicitly get T from Task<T> by calling Task.Result. Note that the Result property will block async code, and should be used carefully.

Try:

private async void button1_Click(object sender, EventArgs e)
{
    var s = await methodAsync();
    MessageBox.Show(s.Result);
}
user2388853
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    While this may not be highly recommended, there was an instance where I wanted to get back `Task` content within `catch {}`. I couldn't `await` and `.ToString()` produced incorrect results. This fit the bill. – doubleJ Jun 15 '14 at 03:25
-2
    //source    
    public async Task<string> methodName()
            {
             return Data;
             }

    //Consumption
     methodName().Result;

Hope this helps :)

-2

In my case.

        string ip = _GetStoreIpaddress().Result;


    private async Task<string> _GetStoreIpaddress()
    {
        string _store_iP = "";
        var Ip_address = await App.SQLiteDb.GetItemsAsync();
        if (Ip_address != null)
        {
            _store_iP = Ip_address.ToString();
        }

        return _store_iP;
    }
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    Firstly, this does not answer the question asked. Secondly, this code has really a lot of issues. Very weird notation, which is not even consistent across this tiny method. Showing the Result() call as a part of solution is another big issue. – Wiktor Jan 20 '22 at 13:35