how to make regular expression match only Cyrillic bulgarian letters

Question

Hello I want to replace all the letters from bylgarian alphabet with empty string I've seen this link How to match Cyrillic characters with a regular expression but it doesn't work for me

Here is what I've tried

1. var newstr = strInput.replace(/[\p{IsCyrillic}]/gi, '');

doesn't work!

2. var newstr = strInput.replace(/[\p{Letter}]/gi, '');

also nothing thanks for help;

score 13 · Accepted Answer · answered Feb 02 '13 at 11:04

13

Javascript doesn't support Unicode classes of the form \p{IsCyrillic}.

But, assuming the characters you want to replace are in the Unicode Cyrillic range 0400 - 04FF, you could use:

newstr = strInput.replace( /[\u0400-\u04FF]/gi, '' );

For example:

    var strInput = 'уфхцчшщъhelloЁЂЃЄрстыьэю',
        newstr = strInput.replace( /[\u0400-\u04FF]/gi, '' ); 

    console.log( newstr );    //  'hello'

answered Feb 02 '13 at 11:04

MikeM

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thanks it works! Do you know afunction which will get all of thw special characters #@ +-+>etc. – Tania Marinova Feb 02 '13 at 12:48

score 2 · Answer 2 · answered Feb 02 '13 at 07:31

2

I think that JavaScript RegEx does not support this syntax.

May be this will help?

XRegExp

answered Feb 02 '13 at 07:31

jdb

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score 0 · Answer 3 · answered Mar 19 '16 at 21:01

0

Another way:

Pattern.compile("[А-я]+", Pattern.UNICODE_CHARACTER_CLASS).matcher(strInput ).replaceAll("") ;

Where [А-я]+ is your alphabet.

answered Mar 19 '16 at 21:01

Suvitruf - Andrei Apanasik

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how to make regular expression match only Cyrillic bulgarian letters

3 Answers3

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