Getting all URL parameters using regex

Question

Possible Duplicate:
How can I get query string values?

Trying to get a regex (Javascript).

Input:   url.html?id=14114&yolo=hahaha
Output:  id=14114
         yolo=hahaha

So this is what i have done so far: (\&|\?)(.*?)\=(.*?)

How do I also include the red circled regions?

enter image description here

Do you mean *url.html?id=14114&yolo=hahaha*? – alex Feb 04 '13 at 00:55 — alex, Feb 04 '13 at 00:55

score 41 · Accepted Answer · answered Feb 04 '13 at 00:59

41

How about this pattern:

(\?|\&)([^=]+)\=([^&]+)

answered Feb 04 '13 at 00:59

Sina Iravanian

2

I made a change after he posted. with his help: (\?|\&)([^=]+)\=([^\&]+) – Mathew Kurian Feb 04 '13 at 01:02
I know this is a little late but this answer will not ignore url fragments (anything after the "#"). Try this one: /[(\?|\&)]([^=]+)\=([^]+)/g – webwires Nov 12 '15 at 16:19
6

As in the RFC: https://tools.ietf.org/html/rfc3986#section-3.3 The semicolon(';') character can also be used to delimit parameters, So I think regex pattern should be changed accordingly – TMKasun May 27 '16 at 12:49
2

@TMKasun is right, the expression should match "Matrix-Parameters" too! `(?:\?|&|;)([^=]+)=([^&|;]+)` – Frozen_byte Mar 01 '18 at 15:03
No, it is doesn't work. For example: "url.com?a=bat & man", -> (a=bat, &man) (?) – Franco Gil Feb 03 '21 at 13:02
This pattern assumes param values are nonempty, for example it won't match `a=` in `url.com?a=&b=2`. To allow empty values, use `([^&]*)` instead of `([^&]+)`. – Kalinda Pride Mar 15 '22 at 18:48

score 22 · Answer 2 · edited Jun 30 '20 at 21:39

22

Try using this:

[^&?]*?=[^&?]*

edited Jun 30 '20 at 21:39

Giacomo1968

answered Feb 04 '13 at 01:04

Kent

2 Answers2