I need to get list of elements all css attributes. How can I do that ?
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Do you want to get all the css properties of an element? – rahul Sep 24 '09 at 11:38
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1Yes, I need to get all css attributes that my selected element has. – newbie Sep 24 '09 at 11:41
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related: http://stackoverflow.com/questions/754607/can-jquery-get-all-css-styles-associated-with-an-element – Aziz Sep 24 '09 at 11:42
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Also related: http://stackoverflow.com/questions/1004475/jquery-css-plugin-that-returns-computed-style-of-element-to-pseudo-clone-that-ele – gnarf Sep 24 '09 at 11:58
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Useful answer: `document.defaultView.getComputedStyle(document.body, '')` got from http://stackoverflow.com/questions/2614963/how-do-i-get-all-supported-css-properties-in-webkit – Muhammad Umer Aug 01 '13 at 09:16
4 Answers
Copying the source from SO1004475 - jQuery CSS plugin that returns computed style of element to pseudo clone that element? - Please follow link and upvote there if you find it useful.
It seems ridiculous, but this is probably your best option - makes .css()
with no arguments get an object with all this stuff set.
jQuery.fn.css = (function(css2) {
return function() {
if (arguments.length) { return css2.apply(this, arguments); }
var attr = ['font-family','font-size','font-weight','font-style','color',
'text-transform','text-decoration','letter-spacing','word-spacing',
'line-height','text-align','vertical-align','direction','background-color',
'background-image','background-repeat','background-position',
'background-attachment','opacity','width','height','top','right','bottom',
'left','margin-top','margin-right','margin-bottom','margin-left',
'padding-top','padding-right','padding-bottom','padding-left',
'border-top-width','border-right-width','border-bottom-width',
'border-left-width','border-top-color','border-right-color',
'border-bottom-color','border-left-color','border-top-style',
'border-right-style','border-bottom-style','border-left-style','position',
'display','visibility','z-index','overflow-x','overflow-y','white-space',
'clip','float','clear','cursor','list-style-image','list-style-position',
'list-style-type','marker-offset'];
var len = attr.length, obj = {};
for (var i = 0; i < len; i++) {
obj[attr[i]] = css2.call(this, attr[i]);
}
return obj;
};
})(jQuery.fn.css);
Note that this doesn't capture all possible CSS properties, particularly new ones for CSS3. Here is a list of all standard CSS and stable CSS3 properties, and here's one of hyphen-prefixed vendor-specific properties (such as -moz-border-start
). If you really want all of them, you can glean them from there.
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2Edited to avoid polluting the `jQuery.fn` namespace with a `css2` function. Otherwise, this is great stuff. – Justin Morgan - On strike Apr 12 '13 at 16:14
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@gnarf Note that jQuery since 1.9 can take an array of properies in its css method so the loop is not needed there. – mgol Apr 13 '13 at 09:27
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As of jQuery 1.8, you can do:
$( "#yourElement" ).css( "cssText" );
Which uses the underlying window.getComputedStyle( element ).cssText
. That's the simplest way.

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Thanks! You helped me solve the problem of moving stuff to a certain container in the dom without any styling getting lost! :-) I use it for some pet project, make a HTML page fall apart with box2d... – EJTH Apr 29 '15 at 20:30
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WOW! I love this! Simply the best way if you want a dump of every CSS property in existence! – Leviscus Tempris Dec 03 '16 at 21:47
For inline styles:
var styles = $("#someelement").attr("style");
From there, you should be able to split this string if you need to loop the styles.
To check individual styles, check the docs:

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Perhaps explain what you're trying to accomplish in your question. You may be better off checking for individual styles, or using classes and using .hasClass() - gnarf has a link below otherwise – ScottE Sep 24 '09 at 14:00
$("#div1).css("background-color");
will return the background color property of an element with id div1.
Sorry, I don't know a way to get all the CSS attributes using jQuery.

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