Printing chars and their ASCII-code in C

Question

How do I print a char and its equivalent ASCII value in C?

So far there seems to be no correct answer among the 12 answers. Many fail at limiting the values to the 0 to 127 range as ASCII is a 7 bit encoding, and so far none has solved the problem that the numerical value of a character in C doesn't have to be the *ASCII* value! The system/compiler could also be using something like EBCDIC encoding, then the numerical value of an 'a' would not be the ASCII value of an 'a' in C. — BlackJack, Aug 17 '17 at 17:01

score 43 · Accepted Answer · edited Aug 18 '17 at 04:12

43

This prints out all ASCII values:

int main()
{
    int i;
    i=0;
    do
    {
        printf("%d %c \n",i,i);
        i++;
    }
    while(i<=255);
    return 0;
}

and this prints out the ASCII value for a given character:

int main()
{
    int e;
    char ch;
    clrscr();
    printf("\n Enter a character : ");
    scanf("%c",&ch);
    e=ch;
    printf("\n The ASCII value of the character is : %d",e);
    getch();
    return 0;
}

edited Aug 18 '17 at 04:12

Nisse Engström

4,738
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answered Sep 24 '09 at 15:54

ennuikiller

46,381
14
112
137

5

Your code prints the decimal value created by converting the char to an int. This may be the ascii code on some systems, but then again it may not. – Pete Kirkham Sep 24 '09 at 16:24
1

Why the above program doesnt print ASCII characters from 127 to 160? – CodeCodeCode May 03 '13 at 12:30
6

Pretty sure ASCII stops at 127 – Sep 23 '13 at 23:49
4

Isn't this undefined behavior?? using `%d` to print a `char`?? – user007 Jul 10 '15 at 16:10
2

Sorry, -1 for `getch()`. Terrible example using this non standard funcion. – Iharob Al Asimi Jan 18 '16 at 20:32
1

@user007: No. It is not possible to pass a `char` to a variadic function. Any integer type that is narrower than `int` will be converted to `int` or `unsigned int`. The only case that can cause trouble would be an unusual implementation where `CHAR_MAX` is not representative in a `signed int`, but would cause all sorts of trouble elsewhere. – Nisse Engström Aug 18 '17 at 04:29
Representa**ble**. ...but that would cause all sorts of trouble elsewhere as well. – Nisse Engström Aug 18 '17 at 11:46
1

First of all ASCII has **7** Bits from **0 to 128** (**0x0 to 0x7F**) after that its called **E**ASCII meaning **Extended**Ascii.that is of **8-Bits** and if you need to print **EASCII** then you need **UTF-8** encoding enabled from **Locale.h** header file. – Haseeb Mir Nov 07 '18 at 20:37

MBillock · Answer 2 · 2009-09-24T17:10:08.860

5

Try this:

char c = 'a'; // or whatever your character is
printf("%c %d", c, c);

The %c is the format string for a single character, and %d for a digit/integer. By casting the char to an integer, you'll get the ascii value.

edited Sep 24 '09 at 17:10

answered Sep 24 '09 at 15:57

MBillock

220
1
6

You don't need to cast to `int`, since the standard type promotions will promote `c` into an `int` automatically. – David R Tribble Sep 24 '09 at 16:18

score 1 · Answer 3 · edited Mar 31 '18 at 15:35

1

To print all the ascii values from 0 to 255 using while loop.

#include<stdio.h>

int main(void)
{
    int a;
    a = 0;
    while (a <= 255)
    {
        printf("%d = %c\n", a, a);
        a++;
    }
    return 0;
}

edited Mar 31 '18 at 15:35

Killzone Kid

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37

answered Jan 29 '13 at 08:52

Sudeep Acharya

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2
15

ASCII has 7 bits so **0 to 127** after thats is system defined **EASCII**. – Haseeb Mir Nov 07 '18 at 20:34

score 1 · Answer 4 · answered Jun 19 '15 at 11:53

Nothing can be more simple than this

#include <stdio.h>  

int main()  
{  
    int i;  

    for( i=0 ; i<=255 ; i++ ) /*ASCII values ranges from 0-255*/  
    {  
        printf("ASCII value of character %c = %d\n", i, i);  
    }  

    return 0;  
}

Source: program to print ASCII value of all characters

score 1 · Answer 5 · answered Jul 12 '20 at 15:14

1

#include<stdio.h>
 void main()
{
char a;
scanf("%c",&a);
printf("%d",a);
}

answered Jul 12 '20 at 15:14

Shivam Panchbhai

89
2
11

David R Tribble · Answer 6 · 2017-09-25T16:08:03.017

0

This reads a line of text from standard input and prints out the characters in the line and their ASCII codes:

#include <stdio.h>

void printChars(void)
{
    unsigned char   line[80+1];
    int             i;

    // Read a text line
    if (fgets(line, 80, stdin) == NULL)
        return;

    // Print the line chars
    for (i = 0;  line[i] != '\n';  i++)
    {
        int     ch;

        ch = line[i];
        printf("'%c' %3d 0x%02X\n", ch, ch, (unsigned)ch);
    }
}

edited Sep 25 '17 at 16:08

answered Sep 24 '09 at 16:16

David R Tribble

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`%X` expects an **unsigned** int. – Nisse Engström Aug 18 '17 at 06:30
@NisseEngström - Code corrected, for the truly pedantic. Yes, it's always a good idea to use `unsigned char[]` for text buffers. – David R Tribble Sep 25 '17 at 16:08

score 0 · Answer 7 · edited Feb 08 '15 at 16:40

0

Chars within single quote ('XXXXXX'), when printed as decimal should output its ASCII value.

int main(){

    printf("D\n");
    printf("The ASCII of D is %d\n",'D');

    return 0;

}

Output:

% ./a.out
>> D
>> The ASCII of D is 68

edited Feb 08 '15 at 16:40

gvlasov

18,638
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answered Feb 08 '15 at 16:16

syamantak82

11
1

score 0 · Answer 8 · edited Oct 03 '19 at 20:48

0

Simplest approach in printing ASCII values of a given alphabet.

Here is an example :

#include<stdio.h>
int main()
{
    //we are printing the ASCII value of 'a'
    char a ='a'
    printf("%d",a)
    return 0;
}

edited Oct 03 '19 at 20:48

Yann39

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answered Oct 03 '19 at 16:31

Python-Baby

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Printing chars and their ASCII-code in C

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