mysql inserting different value

Question

$insert = mysql_query("
    INSERT into analytics.pagesummary (Date, avg_load_time, min_load_time, max_load_time) 
    VALUES ($date,$string_avg, $string_min,$string_max)" ) 
    or die('PROBLEM'.mysql_error());

Actual date values = '2013-02-07', '2013-02-08', '2013-02-09' Date values in the database after the query is fired = '2004', '2003', '2002'

Other values being displayed of avg_load_time, min_load_time & max_load_time are correct.

Where are we going wrong. Any help would be appreciated.

[**Please, don't use `mysql_*` functions in new code**](http://bit.ly/phpmsql). They are no longer maintained [and are officially deprecated](https://wiki.php.net/rfc/mysql_deprecation). See the [**red box**](http://j.mp/Te9zIL)? Learn about [*prepared statements*](http://j.mp/T9hLWi) instead, and use [PDO](http://php.net/pdo) or [MySQLi](http://php.net/mysqli) - [this article](http://j.mp/QEx8IB) will help you decide which. If you choose PDO, [here is a good tutorial](http://j.mp/PoWehJ). — j0k, Feb 09 '13 at 08:18

score 1 · Answer 1 · edited May 23 '17 at 12:27

because the values were not wrap in a single quote and mysql implicitly cast the values silently, it should be

INSERT INTO analytics.pagesummary (Date, avg_load_time, min_load_time, max_load_time) 
VALUES ('$date', '$string_avg', '$string_min', '$string_max')

The reason why 2013-02-07 when inserted becomes 2004 is because it performs arithmethic operation such that

2013 - 02 = 2011 - 07 = 2004
2013 - 02 = 2011 - 08 = 2003
2013 - 02 = 2011 - 09 = 2002

As a sidenote, the query is vulnerable with SQL Injection if the value(s) of the variables came from the outside. Please take a look at the article below to learn how to prevent from it. By using PreparedStatements you can get rid of using single quotes around values.

How to prevent SQL injection in PHP?

mysql inserting different value

1 Answers1