Bitwise operator unexpected behavior

Question

Can someone explain this java bitwise operator behavior??

System.out.println(010 | 4); //  --> 12
System.out.println(10 | 4);  //  --> 14

Thank you!

This has nothing to do with bitwise operations, as your own examples demonstrate. — T.J. Crowder, Feb 10 '13 at 15:36

score 6 · Accepted Answer · edited Feb 10 '13 at 15:37

6

The first number is interpreted as octal. So 010 == 8.

Starting from that, it is easy to see, that

8d | 4d == 1000b | 0100b == 1100b == 12d

The second number is interpreted to be decimal, which yields

10d | 4d == 1010b | 0100b == 1110b == 14d

(Where d indicates a decimal number and b indicates a binary one.)

edited Feb 10 '13 at 15:37

T.J. Crowder

answered Feb 10 '13 at 15:33

Sirko

Also it is related to http://stackoverflow.com/questions/565634/integer-with-leading-zeroes ... but i didn't figure that were the reason till now. Thank you. – Rafael Feb 10 '13 at 15:38

1 Answers1