remove leading 0 in exponential format in python

Question

I have the following code in Python 3.1

"{0:.6E}".format(9.0387681E-8)

Which gives a string of 9.038768E-08, but I want the string 9.038768E-8 with the leading 0 of E-08 removed. How should I go about this?

score 3 · Accepted Answer · answered Feb 13 '13 at 21:12

3

you could do something like this

"{0:.6E}".format(9.0387681E-8).replace("E-0", "E-")

or better as JBernardo suggests

format(9.0387681E-8, '.6E').replace("E-0", "E-")

You need to do a replace for E+0 as well if you have big numbers

answered Feb 13 '13 at 21:12

John La Rooy

For single objects, it's better to use the `format` function: `format(9.0387681E-8, '.6E')` – JBernardo Feb 13 '13 at 21:13
@gnibbler: I retract my comment; I think your answer is safe. (+1) – unutbu Feb 13 '13 at 21:18
@unutbu, putting it in a function and testing the corner cases would be a good idea regardless. – John La Rooy Feb 13 '13 at 21:24

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