What's wrong with my except?

Question

I've got a SyntaxError on my except:

try:
    opts, args = getopt.getopt(sys.argv[1:], 'P:D:H:d:u:p:nvhmJi:c:Ml:TB:',
            ['host=', 'port=', 'directory=', 'user=', 'password=',
             'daemon=', 'noauth', 'help', 'verbose', 'mysql', 
             'icounter=', 'config=', 'nolock', 'nomime', 'loglevel', 'noiter',
             'baseurl='])
except getopt.GetoptError, e:
    print usage
    print '>>>> ERROR: %s' % str(e)
    sys.exit(2)

I get the error:

File "main.py", line 199

except getopt.GetoptError, e:

SyntaxError: invalid syntax

Anyone have any idea?

Check out this discussion regarding the same issue: http://stackoverflow.com/questions/2535760/python-try-except-comma-vs-as-in-except — Forhad Ahmed, Feb 16 '13 at 09:33

georg · Answer 1 · 2013-02-16T22:58:09.833

59

You use python3 and in python3 the raise syntax no longer accepts comma-separated arguments.

Use as instead:

except getopt.GetoptError as e:

This form is also backwards-compatible with 2.6 and 2.7.

edited Feb 16 '13 at 22:58

answered Feb 16 '13 at 09:54

georg

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I'd add that if the OP wants code that's compatible with python<2.6 then he should use `except getopt.GetoptError:` and then retrieve the error information using `sys.exc_info()` – Bakuriu Feb 16 '13 at 10:48

score 9 · Answer 2 · answered Feb 16 '13 at 09:30

9

Your syntax is invalid for catching the exception

You should have written except getopt.GetoptError as e: instead of except getopt.GetoptError, e:

answered Feb 16 '13 at 09:30

Abhijit

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3

This was the correct syntax in earlier versions of Python, though. – tripleee Feb 16 '13 at 10:50

What's wrong with my except?

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