Importing a txt into a dictionary causes python to crash?

Question

I've followed the first answer on this thread:

Python - file to dictionary?

And whenever I try and run the script, Python just closes. everything, even my other scripts I'm not working on.

Here's what I've got written, its virtually the same:

    d = {}
with open("C:\Users\Owatch\Documents\Python\FunStuff\nsed.txt") as f:
    for line in f:
        (key, val) = line.split()
        d[int(key)] = val

print(d)

The only thing I changed was the file location as that's what I understood I was to include to fix the error about not finding the file

Elaboration:

Here is the code I am supposed to use:

d = {}
with open("file.txt") as f:
    for line in f:
       (key, val) = line.split()
       d[int(key)] = val

Here is what I did, adding a file path in place of file.txt, and having it so that it would or should print the dictionary d as soon as it's done.

d = {}
with open("C:\Users\Owatch\Documents\Python\Unisung Net Send\nsed.txt") as f:
    for line in f:
        (key, val) = line.split()
        d[int(key)] = val

print(d)

The problem is I cannot even run this, as Python just crashes, I am running version: 3.1

Answer 1

Change

open("C:\Users\Owatch\Documents\Python\FunStuff\nsed.txt")

to

open(r"C:\Users\Owatch\Documents\Python\FunStuff\nsed.txt")

Otherwise "\nsed" will be taken as a newline plus "sed".

Update:

From your input file, problem is:

d[int(key)] = val

Because your first column are letters, not integers. Change it to:

d[key] = val

Or: (if you prefer number keys)

d[ord(key) - ord('a')] = val

Answer 2

Use a r'' raw string literal to prevent Python from interpreting \n as a newline:

with open(r"C:\Users\Owatch\Documents\Python\Unisung Net Send\nsed.txt") as f:

or use double backslashes:

with open("C:\\Users\\Owatch\\Documents\\Python\\Unisung Net Send\\nsed.txt") as f:

or forward slashes instead:

with open(r"C:/Users/Owatch/Documents/Python/Unisung Net Send/nsed.txt") as f:

All three versions are valid on Windows.

Answer 3

Change d[int(key)] to d[ord(key)]