programmatic storyboard for universal iOS 6 app

Question

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Attributes inspector

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Execution aborts when I implement the code suggested in the answer provided .

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This fine question and answer does not quite deal with my Universal app which had both a iPhone and iPad xibs and now wants to use a storyboard.

This is the xib based BSAppDelegate.m (before storyboard)

    #import "BSAppDelegate.h"
    #import "BSViewController.h"

    @implementation BSAppDelegate

    NSString *receivedData;

    - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
    {
        // Override point for customization after application launch.
        // return YES;
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
        // Override point for customization after application launch.
        if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
            self.viewController = [[BSViewController alloc] initWithNibName:@"BSViewController_iPhone" bundle:nil];
        } else {        
            self.viewController = [[BSViewController alloc] initWithNibName:@"BSViewController_iPad" bundle:nil];
    }
        self.window.rootViewController = self.viewController;   
        [self.window makeKeyAndVisible];
        return YES;
    }

I have tried to insert the following code right after the else above but I cannot quite complete the code fix which needs to set self.viewController to be compatible with the above code.

UIStoryboard *sb = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil];
UIViewController *vc = [sb instantiateViewControllerWithIdentifier:@"BSViewController"];
vc.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal;
[self presentViewController:vc animated:YES completion:NULL];

Can you show me how to fix my code, please? I am using Xcode 4.5.2 and developing for iOS 6.

Daij-Djan · Accepted Answer · 2013-02-17T17:19:30.630

0

two issues:

just set self.ViewController to your vc which you get from the storyboard :)

    #import "BSAppDelegate.h"
#import "BSViewController.h"

@implementation BSAppDelegate

NSString *receivedData;

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
    // Override point for customization after application launch.
    // return YES;
    self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
    // Override point for customization after application launch.
    if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
        self.viewController = [[BSViewController alloc] initWithNibName:@"BSViewController_iPhone" bundle:nil];
    } else {        
        UIStoryboard *sb = [UIStoryboard storyboardWithName:@"MainStoryboard_iPad" bundle:nil];
        UIViewController *vc = [sb instantiateViewControllerWithIdentifier:@"BSViewController"];
        vc.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal;
        self.viewController = (id)vc;
    }
    self.window.rootViewController = self.viewController;   
    [self.window makeKeyAndVisible];
    return YES;
}

in your storyboard, you have no identifier named 'BSViewController' set so the call instantiateViewControllerWithIdentifier will fail. set the identifier (aka the Storyboard ID) visible in your screenshot

edited Feb 17 '13 at 17:19

answered Feb 17 '13 at 15:28

Daij-Djan

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Updated my question with a image showing the termination message. Please take a look. Your answer looks right, so maybe I have not followed your answer correctly. – zerowords Feb 17 '13 at 16:29
well the error states the storyboard doesn't contain a BSViewController. .... but you try to reference it in your question -- the storyboard seems wrong – Daij-Djan Feb 17 '13 at 16:31
you have to set tge identifier on the VC you want to reference! (in IB) – Daij-Djan Feb 17 '13 at 16:32
id say, click on the first VC (in your image) go to the inspector open the third tab (on the right) and fill out the identifier textbox with 'BSViewController' – Daij-Djan Feb 17 '13 at 16:34
My image is showing the open third tab (Identity inspector) filled out as you say, isn't it? I am going to add another image from the (fourth) Attributes inspector in case that tells something. – zerowords Feb 17 '13 at 16:53
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ah sorry its the storyboard id you have to set thats whats the identifier is called today – Daij-Djan Feb 17 '13 at 17:04
Can you be more specific? I don't know where to set that, other than naming the file `MainStoryboard_iPad.storyboard`. – zerowords Feb 17 '13 at 17:07
I added this comment before your last, but it does not show. I thought I had tried before to change the "Identifier" in this line `UIViewController *vc = [sb instantiateViewControllerWithIdentifier:@"MainStoryboard_iPad"];`, but now it works fine. Anyhow, thanks. That seems to be working. Next I need to post another question about how to handle an `OverlayViewController` which was done as its own nib before, but now I have its overlaid view controller in the storyboard. Stay tuned. – zerowords Feb 17 '13 at 18:10

programmatic storyboard for universal iOS 6 app

1 Answers1