java split () method

Question

I've got a string '123' (yes, it's a string in my program). Could anyone explain, when I use this method:

String[] str1Array =  str2.split(" ");

Why I got str1Array[0]='123' rather than str1Array[0]=1?

If none of the answers below work, you probably have a string other than `'123'` in your program. There might be some spaces here and there that you are overlooking. — Sanchit, Feb 19 '13 at 11:42

Achintya Jha · Answer 1 · 2013-02-19T11:44:48.180

3

str2.split("") ;

Try this:to split each character in a string . Output:

[, 1, 2, 3]

but it will return an empty first value.

str2.split("(?!^)");

Output :

[1, 2, 3]

edited Feb 19 '13 at 11:44

answered Feb 19 '13 at 11:25

Achintya Jha

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1

@Leo That will kind of give you almost what you request. It will yield the array `{"", "1", "2", "3"}`. – Alderath Feb 19 '13 at 11:33
@Leo See my answer I think second one is what you wanted. – Achintya Jha Feb 19 '13 at 11:47

Darren · Accepted Answer · 2013-02-19T11:31:46.343

3

str2 does not contain any spaces, therefore split copies the entire contents of str2 to the first index of str1Array.

You would have to do:

 String str2 = "1 2 3";
 String[] str1Array =  str2.split(" ");

Alternatively, to find every character in str2 you could do:

for (char ch : str2.toCharArray()){
    System.out.println(ch);
}

You could also assign it to the array in the loop.

edited Feb 19 '13 at 11:31

answered Feb 19 '13 at 11:26

Darren

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score 2 · Answer 3 · answered Feb 19 '13 at 11:27

the regular expression that you pass to the split() should have a match in the string so that it will split the string in places where there is a match found in the string. Here you are passing " " which is not found in '123' hence there is no split happening.

score 1 · Answer 4 · answered Feb 19 '13 at 11:25

1

Because there's no space in your String. If you want single chars, try char[] characters = str2.toCharArray()

answered Feb 19 '13 at 11:25

Tedil

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score 1 · Answer 5 · answered Feb 19 '13 at 11:25

1

Simple...You are trying to split string by space and in your string "123", there is no space

answered Feb 19 '13 at 11:25

Renjith

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you know, String[] str1Array = str2.split("") ; It doesn't work too( – Leo Feb 19 '13 at 11:26

score 1 · Answer 6 · answered Feb 19 '13 at 11:27

This is because the split() method literally splits the string based on the characters given as a parameter.

We remove the splitting characters and form a new String every time we find the splitting characters.

String[] strs =  "123".split(" ");

The String "123" does not have the character " " (space) and therefore cannot be split apart. So returned is just a single item in the array - { "123" }.

score 1 · Answer 7 · answered Feb 19 '13 at 11:40

To do the "Split" you must use a delimiter, in this case insert a "," between each number

    public static void main(String[] args) {
    String[] list = "123456".replaceAll("(\\d)", ",$1").substring(1)
            .split(",");
    for (String string : list) {
        System.out.println(string);
    }
}

score 0 · Answer 8 · answered Mar 24 '15 at 09:27

0

Try this:

String str = "123"; String res = str.split("");

will return the following result:

1,2,3

answered Mar 24 '15 at 09:27

ErezN

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java split () method

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