I want to process a (very poorly defined) html, which has the information grouped in pairs of rows, like this:
<html>
<body>
<table>
<tr>
<td>
<font >
<a href="a">ABC</a></font>
</td>
</tr>
<tr>
<td height="50">
<font>When:</font><font>19-1-2013</font>
<b><font> </font></b>
<font>Where:</font><font>Here</font>
<font>Who:</font><font>Me</font>
</td>
</tr>
<tr>
<td>
<font >
<a href="b">EFG</a>
</font>
</td>
</tr>
<tr>
<td height="50">
<font>When:</font><font>19-2-2013</font>
<b><font> </font></b>
<font>Where:</font><font>There</font>
<font>Who:</font><font>You</font>
</td>
</tr>
<tr>
<td>
<font >
<a href="c">HIJ</a>
</font>
</td>
</tr>
<tr>
<td height="50">
<font>When:</font><font>19-3-2013</font><b>
<font> </font></b>
<font>Where:</font><font>Far away</font>
<font>Who:</font><font>Him</font>
</td>
</tr>
</table>
</body>
</html>
To this, after several iterations, I arrived at this code to achieve what I want:
import Data.List
import Control.Arrow.ArrowNavigatableTree
import Text.XML.HXT.Core
import Text.HandsomeSoup
group2 [] = []
group2 (x0:x1:xs) = [x0,x1]:(group2 xs)
countRows html = html >>> deep (hasName "tr") >. length
parsePage sz html = let
n x = deep (hasName "tr") >. (( -> a !! x) . group2 ) >>> unlistA
m = deep (hasName "td") >>> css "a" /> getText
o = deep (hasName "td") >>> hasAttr "height" >>> (css "font" >. (take 1 . drop 4)) >>> unlistA /> getText
p x = (((n x) >>> m) &&& ((n x) >>> o))
in html >>> catA [p x | x <- [0..sz]]
main = do
dt <- readFile "test.html"
let html = parseHtml dt
count <- (runX . countRows) html
let cnt = ((head count) `div` 2) - 1
prcssd <- (runX . (parsePage cnt)) html
print prcssd
And the result is: [("ABC","Here"),("EFG","There"),("HIJ","Far away")]
However, I don't think this is a very good aproach, having to count the rows first. Is there a better way of doing this grouping using HXT? I've tried the &&& operator with little luck.
The question at extract multiples html tables with hxt, while useful, presents a simpler situation, I believe.