retrieve child elements of svg g

Question

I'm trying to retrieve the value of svg g element. Below is my code

<div id="chart">
    <svg width="1386" height="186">
    <g transform="translate(0,0)">    
    <g><circle class="node highlight" r="17.603478526018918" style="fill: #008000;" cx="521.2058097619438" cy="67.43023189750437"></circle>
    </g>
    <g><text class="label highlight" dx="22.603478526018918" dy=".35em" transform="translate(521.2058097619438,67.43023189750437)">CNN</text>
    </g>
    </g>
    </svg>
</div>

I want to access the third 'g' element value i.e. 'CNN' in above case. How can I do it using jQuery.

Jai · Answer 1 · 2013-02-21T11:18:47.107

0

Try this:

console.log($('#chart').find('g').eq(2).text());

or this way:

console.log($('#chart').find('text').eq(0).text());

even a better one:

$('#chart g').find('text').text();

edited Feb 21 '13 at 11:18

answered Feb 21 '13 at 11:13

Jai

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score 0 · Answer 2 · answered Feb 21 '13 at 11:14

s = '<div id="chart"><svg width="1386" height="186"><g transform="translate(0,0)"><g><circle class="node highlight" r="17.603478526018918" style="fill: #008000;" cx="521.2058097619438" cy="67.43023189750437"></circle></g><g><text class="label highlight" dx="22.603478526018918" dy=".35em" transform="translate(521.2058097619438,67.43023189750437)">CNN</text></g></g></svg></div>'

$('g:nth-of-type(2)',$(s))

retrieve child elements of svg g

2 Answers2

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