How do I call a public static void that is in a different class.

Question

I have 2 classes, MainActivity and MainGame. If I have a public static void in MainActivity, and one in MainGame. How would I execute the one in MainGame from MainActivity?

For example, I have this:

Main Activity:

public static void 1()
{
2();
}

Main Game:

public static void 2()
{
//blah blah blah
}

ClassName.methodName, though "2" is not a valid method name. — Hot Licks, Feb 23 '13 at 02:41
To understand what are all the valid characters allowed for Java method name. Check out [here](http://docs.oracle.com/javase/specs/jls/se7/html/jls-3.html#jls-3.8) or [here](http://stackoverflow.com/questions/10211135/java-valid-character-for-method-name). — Jayamohan, Feb 23 '13 at 02:47
What is the relation of this question with `Android`, it is general. — Govind Balaji, Feb 23 '13 at 03:19

score 4 · Accepted Answer · answered Feb 23 '13 at 02:35

4

2 isn't a valid method name I think, but if it were you'd just do:

MainActivity.2();

but let's say it isn't and you called it two instead, then maybe you're looking for

public class MainGame {
    public static void one() {
        System.out.println("called one()");
    }
}

public class MainActivity {

    public static void two() {
        MainGame.one();
    }

}

answered Feb 23 '13 at 02:35

rainkinz

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2 was basically just what I put there to try to make it easier to understand, but yeah, that worked, thanks a lot! – user2101454 Feb 23 '13 at 02:39
Great. Hopefully you're all set now. – rainkinz Feb 23 '13 at 02:40

score 1 · Answer 2 · answered Feb 23 '13 at 03:17

In Java All Names must start with a '_' or alphabet.

So, we can take the method names 1 as _1 and 2 as _2.

The syntax for calling static methods in other classes is ClassName.MethodName(arguments).
So, in this case you would change the code as follows:

class MainActivity{
public static void _1()
{
MainGame._2();
}
}
class MainGame{
public static void _2()
{
//blah blah blah
}
}

How do I call a public static void that is in a different class.

2 Answers2