python, how to sort tuple or list with case insensitive?

Question

I have these two lists and I combine them by zip then I want to sort them but it gives me this result (Ard,Ger,Sla,ard) while I wanted to be (ard,Ard,Ger,Sla). any idea?

N = ["ard","Ard","Ger","Sla"]
L = ["7","4","2","3"]
x=zip(N,L)
x.sort()
for i in x:
    print i[0]

score 6 · Accepted Answer · answered Feb 26 '13 at 05:50

6

Pass a key argument to sort:

x.sort(key=lambda (a, b): (a.lower(), b))

The output is:

Ard
ard
Ger
Sla

answered Feb 26 '13 at 05:50

Blender

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Thanks it worked. but I tried a.upper() to give ard,Ard .... but gave same result. – jesy2013 Feb 26 '13 at 06:02
@jesy2013: The number is smaller, so it'll always sort that way. – Blender Feb 26 '13 at 06:05
potentially hackish but **disclaimer** - *before morning coffee*: `x.sort(key=lambda (a, b): (a.lower(), cmp(a.lower(), a), b))` – Jon Clements Feb 26 '13 at 06:22

python, how to sort tuple or list with case insensitive?

1 Answers1