Decorator and error function() argument 1 must be code, not str

Question

I have next code

def timer_dec(f):
    def wrapper(*args, **kwargs):
        t = time.time()
        args[0].debug('<{}> start'.format(f.__name__))
        res = f(*args, **kwargs)
        args[0].debug('<{}> finish'.format(f.__name__))
        args[0].debug("Working time for function <%s>: %f" % (f.__name__, time.time() - t))
        return  res

    return wrapper

This is works fine:

@timer_dec
class A(object):
  pass

But this is not working:

@timer_dec
class A(object):
  pass

class B(A):
  pass

TypeError: Error when calling the metaclass bases function() argument 1 must be code, not str

Python version is 2.7

Could you give an example of a decorator for class? – ngelik Mar 01 '13 at 10:38 — ngelik, Mar 01 '13 at 10:38

score 4 · Accepted Answer · edited May 23 '17 at 10:30

4

You seem to be using a function decorator as a class decorator.

@timer_dec
class A(object):
  pass

is equivalent to

class A(object):
  pass
A = timer_dec(A)

Because timer_dec returns a function, A is now a function.

You can create a class decorator that applies a function decorator to all methods of the class. See here for an example: Alex Martelli's answer to Applying python decorators to methods in a class

edited May 23 '17 at 10:30

Community

1
1

answered Mar 01 '13 at 10:32

Janne Karila

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This is true for Python 3 too, which gives the same useless error message. – c z Apr 04 '17 at 09:31

score 0 · Answer 2 · answered Mar 01 '13 at 10:31

0

Your decorator is returning a function. Thus, after the decorator call, the name "A" is bound to a function, not a class. Then, you try to inherit B from the function A, which is illegal.

answered Mar 01 '13 at 10:31

shx2

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Decorator and error function() argument 1 must be code, not str

2 Answers2