Python - How to add zeros to and integer/string?

Question

I'm without clues on how to do this in Python. The problem is the following: I have for example an orders numbers like:

1
2
...
234567

I need to extract only the 4 last digits of the order number and if the order number have less than 4 digits I will substitute with zeros.

The required output is like this:

Any clues? I'm a bit lost with this one.

Best Regards,

The question is not an exact duplicate, as it looks for padding AND cutting to fix size — Don, Mar 01 '13 at 22:53

Don · Accepted Answer · 2013-03-01T22:48:47.157

5

Try this:

>>> n = 234567
>>> ("%04d"%n)[-4:]
'4567'

Explanation (docs):

"%04d"%n --> get a string from the (d)ecimal n, putting leading 0s to reach 4 digits (if needed)

but this operation preserves all the digits:

>>> n = 7
>>> "%04d"%n
'0007'   
>>> n = 234567
>>> "%04d"%n
'234567'

So, if you want last 4 digits, just take the characters from position -4 (i.e. 4 chars from the right, see here when dealing with 'slice notation'):

>>> n = 234567
>>> ("%04d"%n)[-4:]
'4567'

edited Mar 01 '13 at 22:48

answered Mar 01 '13 at 18:41

Don

Great! It works. What does exactly the "%04d"?. Can you explain the magic? Thank you very much. – André Mar 01 '13 at 18:44

score 2 · Answer 2 · answered Mar 01 '13 at 18:42

2

Something like the following:

>>> test = [1, 234567]
>>> for num in test:
        last4 = str(num)[-4:]
        print last4.zfill(4)

0001
4567

answered Mar 01 '13 at 18:42

Jon Clements

2 Answers2