Before tellimg me to google, please note that Google will not me search "<<" characters.
I have found the following:
data is a byte array.
int ResultChannel = data[1] + (data[2] << 8)
How does the << work?
Before tellimg me to google, please note that Google will not me search "<<" characters.
I have found the following:
data is a byte array.
int ResultChannel = data[1] + (data[2] << 8)
How does the << work?
Shift Left.
In C-inspired languages, the left and right shift operators are "<<" and ">>", respectively. The number of places to shift is given as the second argument to the shift operators. For example,
x = y << 2;
assigns x the result of shifting y to the left by two bits.
<< is a left shift operator
The left-shift operator (<<) shifts its first operand left by the number of bits specified by its second operand. The type of the second operand must be an int or a type that has a predefined implicit numeric conversion to int.
static void Main()
{
int i = 1;
long lg = 1;
// Shift i one bit to the left. The result is 2.
Console.WriteLine("0x{0:x}", i << 1);
// In binary, 33 is 100001. Because the value of the five low-order
// bits is 1, the result of the shift is again 2.
Console.WriteLine("0x{0:x}", i << 33);
// Because the type of lg is long, the shift is the value of the six
// low-order bits. In this example, the shift is 33, and the value of
// lg is shifted 33 bits to the left.
// In binary: 10 0000 0000 0000 0000 0000 0000 0000 0000
// In hexadecimal: 2 0 0 0 0 0 0 0 0
Console.WriteLine("0x{0:x}", lg << 33);
}
It a bit shift operator.
It shifts the bits to the left.
For example: the 5 << 3 returns a value that is 5 shifted three placed to the left. Five in binary is:
00000101
And if you shift that three places to the left you get:
00101000
Which is 40.