I'm playing around with SFINAE, but I'm trying to get some meaningful compiler-error information while dealing with macro-generated code. I used THIS answer to get the following running: (I want to check with member_test(a) whether Type A has some previously defined members)
//Check for member variable with given name.
#define CREATE_MEMBER_VAR_CHECK(var_name) \
\
template<typename T, typename = std::true_type> \
struct has_member_var_##var_name : std::false_type {}; \
\
template<typename T> \
struct has_member_var_##var_name< \
T \
, std::integral_constant< \
bool, std::is_member_object_pointer<decltype(&T::var_name)>::value \
> \
> : std::true_type {};
#define MEMB_CHECK_WRAPPER(r, data, elem) CREATE_MEMBER_VAR_CHECK(elem)
#define CREATE_ENABLE_IF_CLAUSE(var_name) \
class = typename std::enable_if<has_member_var_##var_name<T>::value>::type
#define ENABLE_IF_CLAUSE_WRAPPER(r, data, i, elem) \
BOOST_PP_COMMA_IF(i) CREATE_ENABLE_IF_CLAUSE(elem)
#define TO_MEMBER_TEST(member_seq) \
BOOST_PP_SEQ_FOR_EACH(MEMB_CHECK_WRAPPER, _, member_seq) \
\
template < typename T, \
BOOST_PP_SEQ_FOR_EACH_I(ENABLE_IF_CLAUSE_WRAPPER, _, member_seq) \
> \
void member_test(const T & ) \
{ \
std::cout << "works!!\n\n"; \
}
When I then do the following, then everything will be fine:
TO_MEMBER_TEST((x)(y)(z))
struct A { int x, y, z; };
int main(int argc, char const *argv[])
{
A a;
member_test(a);
}
However, when I use TO_MEMBER_TEST((x)(y)(z)(dummy))
instead, then the code won't compile (as intended), because member_test(A&) is not defined anymore, because A.dummy doesn't exists. The compiler will give me something like:
template argument deduction/substitution failed: error: no type named 'type' in 'struct std::enable_if'
How can I say something like 'There is no member dummy.' instead (e.g. with static_asserts)?