array declaration of shellscript doesnot work in scheduled cron job?

Question

I have created a shell script named "script.sh" which reads an arrays elements and prints it on terminal. The script is as follows:

 arr=("hello" "world")
for i in ${arr[@]}
do
echo  $i;
done

It gives expected output i.e 'Hello World' on executing it in terminal, but if I schedule the same script in crontab jobs to get executed automatically every minute and store the output in another file,the job fails and gives

/home/vikash/script.sh: 1: Syntax error: "(" unexpected error.

The crontab job to execute the script every minute and store the output in another file is as follows:

* * * * * $HOME/script.sh >> $HOME/output.log 2>&1

How to use array in this scenario?? please help.

... or, alternatively, a `SHELL=/bin/bash` line in your crontab, assuming your version of `cron` supports that, which most modern Linux distros seem to... — twalberg, Mar 04 '13 at 19:53

score 5 · Answer 1 · answered Mar 21 '15 at 12:38

5

Add this before the first line of your script:

#!/bin/bash

answered Mar 21 '15 at 12:38

in my case the shebang was not on the firstline (I had a # line before the shebang). So yes it must be absolutely the first line of the script. – Nico Jun 13 '23 at 15:20

score 0 · Answer 2 · answered Mar 10 '17 at 08:20

0

if this question is still valid, just run your script with

bash script.sh

I also tried it with sh somehow it is not working with sh but with bash it suns smooth.

answered Mar 10 '17 at 08:20

Umesh Kaushik

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array declaration of shellscript doesnot work in scheduled cron job?

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