8

im trying to make a random color generator but i dont want similar colors to show up in the arrayList

public class RandomColorGen {

public static Color RandColor() {
    Random rand = new Random();
    float r = rand.nextFloat();
    float g = rand.nextFloat();
    float b = rand.nextFloat();
    Color c = new Color(r, g, b, 1);
    return c;

}

public static ArrayList<Color> ColorList(int numOfColors) {
    ArrayList<Color> colorList = new ArrayList<Color>();
    for (int i = 0; i < numOfColors; i++) {
        Color c = RandColor();
        if(similarcolors){
            dont add
        }
        colorList.add(c);

    }
    return colorList;
}

}

I'm really confused please help :)

I82Much
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Ryan Maddox
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2 Answers2

14

Implement a similarTo() method in Color class.

Then use:

public static ArrayList<Color> ColorList(int numOfColors) {
    ArrayList<Color> colorList = new ArrayList<Color>();
    for (int i = 0; i < numOfColors; i++) {
        Color c = RandColor();
        boolean similarFound = false;
        for(Color color : colorList){
            if(color.similarTo(c)){
                 similarFound = true;
                 break;
            }
        }
        if(!similarFound){
            colorList.add(c);
        } 

    }
    return colorList;
}

To implement the similarTo:

Take a look at Color similarity/distance in RGBA color space and finding similar colors programatically. A simple approach can be:

((r2 - r1)2 + (g2 - g1)2 + (b2 - b1)2)1/2

And:

boolean similarTo(Color c){
    double distance = (c.r - this.r)*(c.r - this.r) + (c.g - this.g)*(c.g - this.g) + (c.b - this.b)*(c.b - this.b)
    if(distance > X){
        return true;
    }else{
        return false;
    }
}

However, you should find your X according to your imagination of similar.

Community
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StarPinkER
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5

I tried this and it worked very well:

Color c1 = Color.WHITE;
Color c2 = new Color(255,255,255);

if(c1.getRGB() == c2.getRGB()) 
    System.out.println("true");
else
    System.out.println("false");
}

The getRGB function returns an int value with the sum of Red Blue and Green, so we are comparing integers not objects.

Synchro
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Seikon
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    This may be correct but it doesn't answer the question, which is asking to find similar, not just identical colours. – Synchro Aug 04 '14 at 08:05