I have a float: 1.2333333
How do I change it into a two decimal number with a comma as a decimal point separator, eg 1,23?
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dupe: http://stackoverflow.com/questions/316238/python-float-to-decimal-conversion – Ólafur Waage Oct 07 '09 at 09:10
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1@Ólafur Waage - the locale stuff is not in http://stackoverflow.com/questions/316238/python-float-to-decimal-conversion – Dominic Rodger Oct 07 '09 at 09:12
3 Answers
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To get two decimals, use
'%.2f' % 1.2333333
To get a comma, use replace():
('%.2f' % 1.2333333).replace('.', ',')
A second option would be to change the locale to some place which uses a comma and then use locale.format():
locale.setlocale(locale.LC_ALL, 'FR')
locale.format('%.2f', 1.2333333)
Aaron Digulla
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2This is absolutely wrong. the normal `"%f"` string formatter is not locale-dependent. – u0b34a0f6ae Oct 07 '09 at 10:04
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Sometimes, it is: https://bugs.webkit.org/show_bug.cgi?id=18994 I've improved my answer to avoid the ambiguity. – Aaron Digulla Oct 07 '09 at 10:39
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@FlorianPilz: Not with my version of Python and not [according to the documentation](https://docs.python.org/2/library/stdtypes.html#str.replace) – Aaron Digulla Apr 10 '14 at 07:02
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@AaronDigulla I removed my comment, since I explained the behavior in Ruby. Sadly I cannot change my vote. – Florian Pilz Apr 25 '14 at 13:32
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The locale module can help you with reading and writing numbers in the locale's format.
>>> import locale
>>> locale.setlocale(locale.LC_ALL, "")
'sv_SE.UTF-8'
>>> locale.format("%f", 2.2)
'2,200000'
>>> locale.format("%g", 2.2)
'2,2'
>>> locale.atof("3,1415926")
3.1415926000000001
u0b34a0f6ae
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If you don't want to mess with the locale, you can of course do the formatting yourself. This might serve as a starting point:
def formatFloat(value, decimals = 2, sep = ","):
return "%s%s%0*u" % (int(value), sep, decimals, (10 ** decimals) * (value - int(value)))
Note that this will always truncate the fraction part (i.e. 1.04999 will print as 1,04).
unwind
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