Calculate age with PHP in YYYY MM DD format

Question

I'm trying to get this code to calculate the age from a field in a form.

<?php
   $birthDate = "$dob";

   $birthDate = explode("-", $birthDate);

   $age = (date("md", date("U", mktime(0, 0, 0, $birthDate[0], $birthDate[1], $birthDate[2]))) > date("md") ? ((date("Y")-$birthDate[2])-1):(date("Y")-$birthDate[2]));
   echo "Age is: ".$age;
?>

but i can't get it to use the format of the input field which is YYYY-MM-DD.

If i change $dob to a date in the eu standard format that PHP uses it works like a charm.

Is there some easy way to correct this?

Possible duplicate of http://stackoverflow.com/questions/4060004/calculate-age-in-javascript — Maen, Mar 11 '13 at 15:01

score 1 · Accepted Answer · answered Mar 11 '13 at 15:05

Always be careful with date notation (ie. order of years, months and days).

This is working (original code adapted):

<?php
$birthDate = "1984-05-21";

$birthDate = explode("-", $birthDate);

$age = (date("md", date("U", mktime(0, 0, 0, $birthDate[2], $birthDate[1], $birthDate[0]))) > date("md") ? ((date("Y")-$birthDate[0])-1):(date("Y")-$birthDate[0]));
echo "Age is: ".$age;
?>

huysentruitw · Answer 2 · 2013-03-11T15:30:00.583

0

Use the DateTime::diff function

Example

<?php
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2013-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%y years');
?>

edited Mar 11 '13 at 15:30

answered Mar 11 '13 at 15:03

huysentruitw

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Ja͢ck · Answer 3 · 2013-03-11T23:42:22.810

0

Use strtotime($dob) to get a timestamp. Then to calculate age in the human way:

list($dob_year, $dob_date) = explode('-', date('Y-md', strtotime($dob)));
list($cur_year, $cur_date) = explode('-', date('Y-md'));

$age = $cur_year - $dob_year - ($dob_date >= $cur_date ? 0 : 1);

edited Mar 11 '13 at 23:42

answered Mar 11 '13 at 15:04

Ja͢ck

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Calculate age with PHP in YYYY MM DD format

3 Answers3