PHP if does not equal to or another does not equal to

Question

I am trying to do a conditional if statement that checks whether the value of a variable $cat_ID is not equal to 19 or 26 then it should echo my $priceToShow variable.

PHP

if(($cat_id != '19') || ($cat_id !='26')){ 
    echo $priceToShow;
}

guy is just showing little bit of his code here. give him a break :D — Bojan Kovacevic, Mar 12 '13 at 12:49

score 14 · Accepted Answer · answered Mar 12 '13 at 12:49

14

If it can be neither 19 nor 26, use an and statement:

if(($cat_ID != '19') && ($cat_id !='26')){ 
    echo $priceToShow;
}

If you have a lot of values to check, use in_array:

$bad_values = array(19, 26, 54);
if (!in_array($cat_ID, $bad_values)) {
    echo $priceToShow;
}

(In this case, strict comparisons are off; you should always cast your data to the type it's expected to be, and then use strict comparison:

$bad_values = array(19, 26, 54);
if (!in_array(intval($cat_ID), $bad_values, true)) {
    echo $priceToShow;
}

)

answered Mar 12 '13 at 12:49

Waleed Khan

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variable names are also case sensitive :) – splash21 Mar 12 '13 at 12:52
@splash21 Oh, they are. – Waleed Khan Mar 12 '13 at 12:53

chim · Answer 2 · 2013-03-12T15:11:05.243

7

This will always return true

You need to use an AND conjunction

of for more than 2 values use ! in_array()

Edit: Absolutely right @Waygood

if ( ! ( $v == 19 || $v == 26 ) ) {
  // do your thing
}

edited Mar 12 '13 at 15:11

answered Mar 12 '13 at 12:50

chim

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demorgans theorum: negate and change operator = OR to != AND e.g. 19 OR 26 -> !=19 AND !=26 http://www.allaboutcircuits.com/vol_4/chpt_7/8.html – Waygood Mar 12 '13 at 12:55

score 0 · Answer 3 · answered Mar 12 '13 at 12:50

0

It might be better to use !in_array(). That'll make it quicker and simpler to add and remove when/if needed

if (!in_array($cat_id, array('19', '26')))
{
  echo $priceToShow;
}

answered Mar 12 '13 at 12:50

Michael

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PHP if does not equal to or another does not equal to

3 Answers3