How can I build a counter in python?

Question

I want to have it so that each time I hit the space bar, the number in the terminal increases by one, so that I can keep a number in my head and not forget it. However, if I use raw_input for this, I have to hit enter each time, which is annoying. How can I make it so that I build a counter that increases a variable by one each time the space bar is pressed?

Here is what I have.

x=0

while x<10000000:
    press = raw_input()
    if  press == "z":
        x=x+1
        print x

http://stackoverflow.com/questions/575650/how-to-obtain-the-keycodes-in-python — Bemmu, Mar 13 '13 at 06:07

score 3 · Answer 1 · answered Mar 13 '13 at 15:16

3

If you're using Windows, there's the msvcrt module. So,

import msvcrt

while x = True:
    keypress = msvcrt.getch()
    if keypress == "z":
        x=x+1
        print x

answered Mar 13 '13 at 15:16

gustavo scharf

31
3

score 0 · Accepted Answer · answered Mar 14 '13 at 19:00

If you are using Linux/Unix, there is the curses module.

import curses

def check_press(scr):
    c = None
    x = 0
    while c != 120: # exit on x
        c = scr.getch()
        if c == 122: # count on 'z'
            x += 1
            scr.addstr(0, 0, "%5d" % x)
            scr.refresh()

if __name__ == '__main__':
    curses.wrapper(check_press)

score 0 · Answer 3 · answered Oct 30 '19 at 12:41

0

import os

while True:
    cmd = "read -n 1 c; print $c"
    key = os.popen(cmd).read()
    if key[0] == "z":
        x=x+1
        print x

answered Oct 30 '19 at 12:41

lanco

1
1

How can I build a counter in python?

3 Answers3