What does [](){} construction mean in c++?

Question

I have this code.

boost::for_each(
    boost::make_iterator_range(
            func(arg1),
            func(arg2)
        ),
        [&d, &f](const a<b>& c)
        {
            something;
        }
);

I understand the iterator part of the code. What is not clear to me is over what we iterate. What does this construction mean? [](){}

[This question](http://stackoverflow.com/questions/7627098/what-is-a-lambda-expression-in-c11) has a pretty good explanation. — chris, Mar 13 '13 at 15:31

score 2 · Accepted Answer · edited Mar 13 '13 at 15:35

2

This is a lambda-expression , an anonymous method/function. You can provide it inline if there is no reason to define a distinct function. [] binds the local parameters either by value [] or by reference [&]. In () you pass your values like in a function call and {} embraces the function body.

See here.

edited Mar 13 '13 at 15:35

David G

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answered Mar 13 '13 at 15:33

bash.d

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What does [](){} construction mean in c++?

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